Given:DE and GH <br> Prove:DFE and GFH

The Ferris wheel has a radius of 70 feet. The distance between the wheel and the ground is 4 feet. The rectangular coordinate sy

Leya [2.2K]

Answer:

The equation of the circular wheel is $x^2+(y-74)^2=(70)^2$ .

Step-by-step explanation:

Given :

Radius of Ferris wheel r = 70 feet.

The distance between the wheel and the ground = 4 feet.

Also, the rectangular coordinate system shown has its origin on the ground directly below the center of the wheel.

So the x coordinate of center of wheel must be 0 , and y coordinate = 70 + 4 = 74

Thus, Coordinates of center = (0,74)

The equation of circle is given by :-

$(x-h)^2+(y-k)^2=r^2$

Now center (h,k) = (0,74) and r = 70 , we get

$x^2+(y-74)^2=(70)^2$

Hence, the equation of the circular wheel is $x^2+(y-74)^2=(70)^2$ .

6 0

3 years ago

True or false: the lateral surface of cone a is exactly 1/2 the lateral surface area of cylinder b

Mazyrski [523]

Answer:

True

Step-by-step explanation:

We have that,

The cone A has the length of the lateral side = h and the height of the cylinder B = h.

Since, the lateral surface areas are given by,

Lateral surface area of cone = $\pi r\times l$ , where l is the length of the lateral side.

So, we get $L_{A}$ = $\pi r\times h$ .

Also, Lateral surface area of cylinder is $2\pi r\times h$ , where h is the height of the cylinder.

So, we get $L_{B}$ = $2\pi r\times h$

Thus, we see that, $L_{A}=\frac{1}{2}\times L_{B}$

Hence, the given statement is correct.

6 0

3 years ago

What are the solutions to the system of equations graphed

sweet-ann [11.9K]

Answer:

The point of intersection between the 2 graphs.

5 0

3 years ago

Which expreion are equivalent to

Makovka662 [10]

The expression equivalent to the expression -90 - 60w is -30(3 + 2w), (-9 - 6w)10 and -20(4.5 + 3w)

We need to find the expressions that are equivalent to given expression

We solve the expression and check,

A) -30(3 + 2w)

-90 - 60w

Yes it is equivalent.

B) (-9 - 6w)10

-90 - 60w

Yes it is equivalent.

C) -3(30 - 20w)

-90 + 60w

No it is not equivalent.

D)(6 + 4w)15

90 + 60w

No it is not equivalent.

E) -20(4.5 + 3w)

-90 - 60w

Yes it is equivalent.

Therefore, The expression equivalent to the expression -90 - 60w is -30(3 + 2w), (-9 - 6w)10 and -20(4.5 + 3w)

To learn more about multiplication refer here

brainly.com/question/10873737

#SPJ4

8 0

1 year ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (

Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

$6, \, 27x^2, \, \frac{405x^4}{4}.$

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

$\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...$

So, for the given function y = 6 sec(3x), we get:

$y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...$

So, the first three nonzero terms in the Maclaurin series are:

$6, \, 27x^2, \, \frac{405x^4}{4}.$

6 0

3 years ago

Given:DE and GH Prove:DFE and GFH