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Sophie [7]
2 years ago
6

Find the domain in interval notation.

Mathematics
1 answer:
Nady [450]2 years ago
6 0

Answer:

<em>x ∈ ( - ∞ , - 8 ) ∪ ( - 8 , 0 ) ∪ ( 0 , 8 ) ∪ ( 8 , ∞ ) </em>

Step-by-step explanation:

x³ - 64x = x( x² - 64 ) ≠ 0 ⇒ x ≠ 0 and x ≠ ± 8

<em>x ∈ ( - ∞ , - 8 ) ∪ ( - 8 , 0 ) ∪ ( 0 , 8 ) ∪ ( 8 , ∞ )</em>

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(a) Write an expression for a number that is<br> three more than r.<br> .
navik [9.2K]

Answer:

r+3

Step-by-step explanation:

r is an expression. To get an expression that is 3 more, just add 3

r+3

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1 year ago
How do you write 0.0896 in scientific notation?
il63 [147K]

Answer: 8.96 × ten to the power of two

Sorry, I couldn't write ten to the power of two in numbers...but you get it right?

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A rectangle and a square have the same area. The length of the rectangle is seventy feet more than two times its width. The leng
Zanzabum

Using the side of the square find the area:

Area = 30^2 = 900 square feet.

The rectangles area is the same, 900 square feet.

Let the width = X

The length would be 2X + 70

Area = length x width

X * 2x+ 70 = 900

This expands to 2x^2 * 70x = 900

Use the quadratic formula to solve for x:

-70 +/- sqrt(70^2-4*2(-900))/2*2

X = 10

Width = x = 10 feet

Length = 2x + 70 = 90 feet

8 0
2 years ago
Ill mark the brainliest if you help me with the these three questions 7,8,9
Nitella [24]

Answer:

7) π  8) 6.25π  9)  16π


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1. How do you determine whether a function is an inverse of another function?
-BARSIC- [3]
<h3>Answer:</h3>
  1. Find the composite of the functions
  2. x/3
  3. All the answers are correct
  4. f(x) = 2+∛(x/3)
  5. f(x) = (x+3)/2
<h3>Step-by-step explanation:</h3>

1. If f(x) and g(x) are inverse functions, then f(g(x)) = g(f(x)) = x. Finding the composite of the two functions will tell you if they are inverses.

2. To find the inverse of a function, swap x and y, then solve for y.

... x = 3y

... x/3 = y . . . . . matches f(x) = x/3

3. A function will pass the vertical line test. If its inverse is also a function, that, too, will pass the vertical line test. Since the inverse of a function is that function reflected across y=x, any inverse function that passes the vertical line test corresponds to an original function that passes the horizontal line test. (A vertical line reflected across y=x is a horizontal line.)

4. See 2.

... x = 3(y -2)³

... (x/3) = (y -2)³ . . . . divide by 3

... ∛(x/3) = y -2 . . . . .take the cube root

... 2+∛(x/3) = y . . . . .add 2

... f(x) = 2+∛(x/3) . . . . is the inverse

5. See 2.

... x = 2y -3

... x+3 = 2y . . . . . add 3

... (x+3)/2 = y . . . .divide by 2

... f(x) = (x+3)/2 . . . .  is the inverse

8 0
3 years ago
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