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Vlad1618 [11]
3 years ago
14

A grocer bought some walnuts for 45¢ per pound and some pecans for 60¢ per pound. He wants to mix the pecans and walnuts togethe

r to form a 90 pound mixture to sell at 55 cents per pound. If x represents the pounds of walnuts used in the mixture, which expression would represent the total cost of the pecans used in the mixture?
Mathematics
1 answer:
ladessa [460]3 years ago
7 0
Cost of walnuts = 45 cents per pound
Weight of walnuts in mixture = x pounds

So, total cost of walnuts in the mixture = 45x
This gives the cost in cents. The cost in dollars will be = 0.45x

Cost of pecans = 60 cents per pound

Since total weight of the mixture is 90 pounds. The weight of pecans in the mixture will be (90 - x) pounds.

So, total cost of pecans in the mixture will be = 60 (90 - x)
This gives the cost in cents, the cost in dollars will be = 0.6 (90 - x)

x pounds of walunts and (90-x) pounds of pecans are mixed to produce a mixture to sell at 55 cents per pound. So,we can set up the equation for this case as:

Cost of Walnuts + Cost of Pecans = Cost of Mixture

0.45x+(90-x)*0.60=90(0.55)

Using this equation, we can find the weight of walnuts, using x we can also find the weight of pecans. From weights we can then calculate the cost of walnuts and pecans used in the mixture.

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A dump truck brought 1⁄3 of a ton of rock on the first trip, 1⁄2 of a ton on the second trip, but on the third trip, had to take
Allisa [31]

Answer:

1/30 of a ton

Step-by-step explanation:

Write this as an expression:

1/3 of a ton and 1/2 of a ton were taken to the site.

4/5 of a ton were remove from the site.

Amount of a ton at the site  =   \frac{1}{3}+ \frac{1}{2}- \frac{4}{5}

Solve the equation by finding <u>common denominators</u> (when the bottom numbers are the same).

(\frac{1}{3}+ \frac{1}{2})- \frac{4}{5}       Focus on the first part. The least common multiple (LCM) of 3 and 2 is "6", which will become the denominator.

For <u>1/3 to become ?/6</u>, multiply top and bottom by 2.

For <u>1/2 to become ?/6</u>, multiply top and bottom by 3.

(\frac{2}{6}+ \frac{3}{6})- \frac{4}{5}

Now we can add the numerators together over the same denominator.

\frac{5}{6}- \frac{4}{5}

Do the same thing as before and change the denominators. The LCM of 6 and 5 is "30".

For <u>5/6 to become ?/30</u>, multiply top and bottom by 5.

For <u>4/5 to become ?/30</u>, multiply top and bottom by 6.

\frac{25}{30}- \frac{24}{30}

Subtract the numerators:

\frac{1}{30}                  Answer in tons

Therefore there was 1/30 of a ton of rock left at the construction site.

7 0
3 years ago
Read 2 more answers
Please help I Think I'm wrong!!!!
Allisa [31]
2n+2(n-4)=56
2n+2n-8=56
4n-8=56
4n=64
n=16

1st side is 16
2nd side is 12
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