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Slav-nsk [51]
3 years ago
5

Using the distance formula, calculate how far Tre threw the ball. (4 points: 2 points for setup, 1 for calculation, 1 for the an

swer).
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

D = 63.717

Step-by-step explanation:

The details that complete the question are:

(x_1,y_1) = (0,42.78)

and

(x_2,y_1)=(90,42.78)

Required

Determine how far the ball travelled

Distance is calculated using:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute values for x's and y's

D = \sqrt{(42.78 - 0)^2+(42.78-90)^2}

D = \sqrt{42.78^2+(-47.22)^2

D = \sqrt{1830.1284+2229.7284

D = \sqrt{4059.8568

D = 63.717

<em>Hence, the ball travelled a distance of 63.717 units</em>

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Levart [38]

Answer:

2.33 units

Step-by-step explanation:

\tan 25\degree =\frac{AC}{5}\\\\0.46630 = \frac{AC}{5}\\\\AC = 0.46630 \times 5\\AC =2.3315\\AC = 2.33 \: units

6 0
3 years ago
Elimination method: ax+by=r, -bx+cy=s
Alex17521 [72]
\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]

Isolate x for ax+by=r

x= \frac{r-by}{a} ; a \neq 0

Subsititute x= \frac{r-by}{a}

-b \frac{r-by}{a} +cy=s

Isolate r for : -b \frac{r-by}{a}+cy=s

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For x : \frac{r-by}{a}

Subsititute r = - \frac{as-acy-b^2y}{b}

x= -\frac{as-acy-b^2y}{b}/a

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The solutions to the system of equations are:

r= -\frac{as-acy-b^2y}{b} and <span> x = \frac{cy-s}{b}
</span>
hope this helps!


3 0
3 years ago
A.
koban [17]

Answer: It would be 4b+44

Step-by-step explanation:

This is the distributive property! so a(b+c)=ab+ac

In this case–4b+44!

6 0
2 years ago
Read 2 more answers
What expression shows the distance on the number line between −12 and −1 ?<br><br> Thxxs! ^^
docker41 [41]
-12 and -1 are 11 units apart.
-12-(-1) = -11
The absolute value which is just the number of units is 11. 
Hope this helps you
4 0
3 years ago
If p=(-4,-1) find Rx-axis (p)
yuradex [85]

Answer:

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Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

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3 years ago
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