Question

Using the distance formula, calculate how far Tre threw the ball. (4 points: 2 points for setup, 1 for calculation, 1 for the answer).

Answer 1

Answer:

$D = 63.717$

Step-by-step explanation:

The details that complete the question are:

$(x_1,y_1) = (0,42.78)$

and

$(x_2,y_1)=(90,42.78)$

Required

Determine how far the ball travelled

Distance is calculated using:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute values for x's and y's

$D = \sqrt{(42.78 - 0)^2+(42.78-90)^2}$

$D = \sqrt{42.78^2+(-47.22)^2$

$D = \sqrt{1830.1284+2229.7284$

$D = \sqrt{4059.8568$

$D = 63.717$

Hence, the ball travelled a distance of 63.717 units