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Rus_ich [418]
3 years ago
14

A survey finds that 40% of students ride in a car to school. Eri would like to estimate the probability that if 3 students were

randomly selected, only 1 rides in a car. To simulate this probability, she lets the numbers 0, 1, 2, and 3 represent a student who rides in a car to school and then 4, 5, 6, 7, 8, and 9 represent a student who does not ride in a car to school. She then has a computer randomly select 3 numbers. She repeats this process for 20 trials. The results of these trials are shown in the table.
468 380 120 220 553 945 935 607 473 490 074 981 692 518 408 954 943 389 594 569

Based on this simulation, what is the estimated probability that only 1 of 3 randomly selected students rides in a car to school?
Mathematics
2 answers:
g100num [7]3 years ago
8 0
First, we analyze the data given:

468 = no student rides a car to school
380 = 2 students 
120 = 3 students
220 = 3 students
553 = 1
945 = none
935 = 1
607 = 1
473 = 1
490 = 1
074 = 1
981 = 1
692 = 1
518 = 1
408 = 1
954 = none
943 = 1 
389 = 1
594 = none 
569 = none 

Total = 20 trials
Number of 1 student trial = 12

Therefore, the probability <span>that only 1 of 3 randomly selected students rides in a car to school is 12/20 = 0.6</span><span />
Butoxors [25]3 years ago
3 0
The answer is 0.60 I know cause I took the test
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4 years ago
Did I do this right????
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Answer:

x = -7, y = -3 yup you did it right!

Step-by-step explanation:

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{-(5 x) + 8 y = 11 | (equation 1)

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Multiply equation 2 by 5/2:

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Multiply equation 2 by -1:

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Collect results:

Answer: {x = -7, y = -3

4 0
2 years ago
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