Question

About 10% of the population has a particular genetic mutation. 700 people are randomly selected. Find the standard deviation for the number of people with the genetic mutation in such groups of 700.

Answer 1

Answer: 7.94

Step-by-step explanation:

The formula to calculate the standard deviation for binomial distribution :-

$\sigma=\sqrt{np(1-p)}$, where n is the number total of trials and p is the probability of getting success in each trial.

Given : The probability of the population has a particular genetic mutation=0.1

If 700 people are randomly selected, then the standard deviation for the number of people with the genetic mutation in such groups of 700 will be :-

$\sigma=\sqrt{700\times0.1(1-0.1)}\\\\\Rightarrow\sigma=\sqrt{63}\\\\\Rightarrow\sigma=7.9372539331\approx7.94$

Hence, the standard deviation for the number of people with the genetic mutation in such groups of 700 = 7.94