(-19)+9=-10, so there is 10 less people on the bus
Answer: cost of 1 pot of ivy = $12
Cost of 1 rose bush =$ 10
Step-by-step explanation:
Step 1
Let rose bushes be represented as r
and pot of ivy be represented as p
such that Amy who spent 82 dollars on 7 rose bushes and 1 pot of ivy can be expressed as
7 r + p = 82----- eqn 1
Rob who spent 74 on 5 rose bushes and 2 pots of ivy can be expressed as
5r +2 p = 74----- eqn 2
Step 2
Solving
7 r + p = 82----- eqn 1
5r +2 p = 74----- eqn 2
By elimination method Multiply eqn 1 by 5 and eqn 2 by 7
35r+ 5p= 410--- eqn 3
35r+ 14p =518--- eqn 4
Subtracting eqn 4 from eqn 3
9p = 108
p = 108/9
p=12
p = pot of ivy = $12
therefore rose bush wll be ( from equation 1)
7r+ p= 82
7r=82-12
7r= 70 r= 70/7
r= rose bush =$ 10
Answer:
y = 4x^5 - 12x^4 + 6x and
y = 5x^3 - 2x
Step-by-step explanation:
The system of equations that can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x are;
y = 4x^5 - 12x^4 + 6x and
y = 5x^3 - 2x
We simply formulate two equations by splitting the left and the right hand sides of the given equation.
The next step is to graph these two system of equations on the same graph in order to determine the solution(s) to the given original equation.
The roots of the given equation will be given by the points where these two equations will intersect.
The graph of these two equations is as shown in the attachment below;
The roots are thus;
x = 0 and x = 0.813
Kent can paint the room 1/5
luannda can paint the room 1/3
(3+5) (5*3) = 8/15 or 0.53 th of the room together but just for kent would be 1/5