Answer:
The image is sideways.
But if your graph is like on the image, then the answer is: {y│-3 ≤ y ≤ 4}
Range is the set of y values
Least function value is -3 and greatest is 4
Part A )a painter leans a ladder up against a building. The base of the ladder is placed 7 feet from the building to reach a hei
ght of 24 feet. How long is the ladder
Part B) The painter uses the same ladder from part A, but now needs to reach a height of 19 feet.How far away does the base of the ladder need to be placed from the building? 
Part B) The painter uses the same ladder from part A, but now needs to reach a height of 19 feet.How far away does the base of the ladder need to be placed from the building?
1 answer:
Answer:
Part A). 25 feet
Part B). 16.25 feet
Step-by-step explanation:
Part A). By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
AC² = (24)² + 7²
AC² = 576 + 49
AC = √625
= 25 feet
Part B). By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
(25)² = (19)² + x²
625 = 361 + x²
x² = 625 - 361
x = √264
x = 16.25 feet
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Step-by-step explanation:
Consider the provided information.
For the condition statement or equivalent "If p then q"
The rule for Contrapositive is: Negative both statements and interchange them.
Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.
Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".
It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".
Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.
Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.
Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"
The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.
Remember negative means opposite.
Contrapositive: If xy < 0 then x<0 and y<0.