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rosijanka [135]
3 years ago
10

PLEASE HELP ME WITH BOTH OF THESE PROBLEMS THIS IS DUE SOON PLEASE HELP ME

Mathematics
2 answers:
iogann1982 [59]3 years ago
7 0

Answer:

Step-by-step explanation:

4.

a)

P = 2width + 2length

8x = 2x + 2 length; 8x-2x = 2 length; 6x=2 length

length = 3x

b)

sides= 1/4 of 3x = 3x/4

perimeter of square = 4* side = 4*3x/4 = 3x

c)

x= 4

P rectangle =8x= 8*4= 32

P square = 3x = 3*4 = 12

32-12 = 20 cm greater is the P rectangle than P of square

d)

A rectangle = 2x*x = 2*4*4 = 32

A square =(3x/4)² = (3*4/4)² = 9

32-9 = 23 cm² greater is the A rectangle than A of square

5.

4Comic+1 Nonfiction

4comic = 8y so 1 comic = 2y

1 nonfiction = (3+7y)+ 2y

a)

1 nonfiction = 7y+2y+3 = 9y+3

b)

total= 8y+9y+3 = 17y+3

if y=4

total = 17*4 +3  = $71

tamaranim1 [39]3 years ago
3 0
Answer is 71 !!! they explained it good but i can back it up because i had the same question
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Circle O has a circumference of approximately 44 in.
julsineya [31]

Answer:

Circumference = 3.1415 (pi) x diameter

44 = 3.1414 x diameter

Diameter = 14.006 or 14 (approximately)

Hope this helped : )

4 0
3 years ago
Evaluate 5x2−9 when x=−2
Elena-2011 [213]

answer: 11

explanation: just plug in -2 for x. the new problem becomes 5(-2)^2 - 9. Negative two squared is 4. 5 times 4 is 20. 20 minus 9 is 11.

3 0
3 years ago
If there was a total of 80 vehicles an a percentage of 70% of cars how much car was used
Korolek [52]

Answer:

56

Step-by-step explanation:

I don't quite understand your question but I assumed you meant what is 70% of 80

4 0
3 years ago
The density of silver is 10.5 g/cm3. find the volume of a silver bar if its mass is 950 g
Mademuasel [1]

950 g * 1 cm^3/10.5g =  950/10.5 cm^3 = 90.476 cm^3

4 0
3 years ago
Read 2 more answers
PLZ HELP ASAP SOLID GEOMETRY WORD PROBLEMS
yan [13]
The volume of the candle initially is:
V=Ab*h
Area of the base of the cylinder: Ab=pi*r^2
pi=3.14
Radius of the base: r=4 cm
Height of the cylinder: h=6 cm

Ab=pi*r^2
Ab=3.14*(4 cm)^2
Ab=3.14*(16 cm^2)
Ab=50.24 cm^2

V=Ab*h
V=(50.24 cm^2)*(6 cm)
V=301.44 cm^3

The candle melts at a constant rate of:
r=(60 cm^3)/(2 hours)=(120 cm^3)/(4 hours)=(180 cm^3)/(6 hours)
r=30 cm^3/hour

The amount of candle melted off after 7 hours is:
A=(30 cm^3/hour)*(7 hours)
A=210 cm^3

The percent of candle that is melted off after 7 hours is:
P=(A/V)*100%
P=[(210 cm^3)/(301.44 cm^3)]*100%
P=(0.696656051)*100%
P=69.66560510%
Rounded to the nearest percent
P=70%

Answer: 70%

8 0
3 years ago
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