1. Coloreen la mitad de los triángulos de azul.
1 answer:
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Theoretically, the number of the vertex comes at the top must be equal for infinitely many numbers of trials, but it's a tedious job to roll the dice for a large number of times. Rolling the tetrahedron only 10 times will not predict the correct result.
Han suspects that this tetrahedron is weighted in some way to make 1 appear more often than the other numbers.
So, check his suspect experimentally with the help of the concept of center of mass. A fair tetrahedron must have the center of mass at the center of the body.
The given tetrahedron has 4 equilateral triangular faces, so at first, measure all the sides of triangular faces and make sure that all are having the same length.
Then, conduct an experiment to check the location of the center of mass.
Hang the tetrahedron by attaching a thin string at the vertex 1 as shown in the figure and observe the base surface ( triangle 234) whether it is parallel to the ground or not.
Now, repeat the same by hanging it with vertices 2, 3, and 4 and observe the base surface.
For the center of mass to be located at the center of the tetrahedron, the base must be parallel to the ground (flat ground).i.e the hanging string must be perpendicular to the base for all the four cases.
If this is so, then the tetrahedron is a fair tetrahedron otherwise not.
Answer:
Step-by-step explanation:
Given: sum of the smallest integer and four times the largest integer out of three consecutive odd integers is 61
To list: numbers from least to greatest
Solution:
Let the three consecutive odd integers be .
According to question,
So, the integers are
Numbers from least to the greatest:
Answer:
<em>24 children</em>
Step-by-step explanation:
If the length of time, y hours, it takes to put a jigsaw puzzle together is inversely proportional to the number of children, x, this is represented as;
k is the constant of proportionality
If it takes 16 children 6 hours to put the jigsaw puzzle together, this means at x = 16, y = 6
Substitute:
6 = k/16
k = 6*16
k = 96
W are to find number of children needed to put the same jigsaw puzzle together in 4 hours, this is done by substituting k = 96 and y = 4 into the expression y = k/x
y = 96/4
y = 24
<em>Hence it will take 24 children to put the same jigsaw puzzle together in 4 hours</em>
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