Answer:
The answer is (6.5,3)
Step-by-step explanation:
The solution is in the image
Please help!! I’ll mark you as brainly
2 answers:
You might be interested in
One way would be to find the distance from the point to the center of the circle and compare it to the radius
for
the center is (h,k) and the radius is r
and the distance formula is
distance between
and 
is
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
≈4.2
≈10.04
do r<D
(8,4) is outside the circle
for
the center is (h,k) and the radius is r
and the distance formula is
distance between
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
do r<D
(8,4) is outside the circle
Given statement is "point where the perpendicular bisectors of the three sides of a triangle intersect".
Perpendicular is basically a vertical line that makes 90 degree angle with the base.
bisector means the line which divides side into two equal parts.
So perpendicular bisector in any triangle will be the line which is drawn on the side of the triangle and perpendicular to that side.
Now these perpendicular bisectors meet at some point.
That point is called circumcenter.
Hence final answer will be "circumcenter".
