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3 years ago

Can somebody help plz it’s due soon?

Mathematics

1 answer:

Snezhnost [94]3 years ago

8 0

The answer is 7/18, basically the amount of people in favour over the Amon t of people in total :)

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Find the mean, the median, and all modes for the data in the given frequency distribution. (Round your answers to one decimal pl

kvasek [131]

Answer: Mean = 7.8

Median = 9

Mode = 2,9

Step-by-step explanation: Mean is the average value of a data set. Mean from a frequency table is calculated as:

$E(X)=\frac{2(10)+3(9)+9(10)+11(7)+12(3)+15(4)+16(3)}{10+9+10+7+3+4+3}$

E(X) = 7.8

Mean for the given frequency distribtuion is 7.8.

Median is the central term of a set of numbers. Median in a frequency table is calculated as:

1) Find total number, n:

n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46

2) Find position, using: $\frac{n+1}{2}$

$\frac{n+1}{2}=\frac{47}{2}$ = 23.5

Median is in the 23.5th position.

3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9

Median for this frequency distribution is 9.

Mode is the number or value associated with the highest frequency.

In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.

Mode for this distribution is 2 and 9.

7 0

3 years ago

Using a pair of compass only construct a triangle ABC such that AB=9cm, angle BAC=60° and angle ABC=45°

Leto [7]

Answer:

AC=5.4 BC=7.2

Step-by-step explanation

180-60-45=75 degree

9/75=AC/45=BC/60

6 0

3 years ago

Which dot plot three TVs in two houses

Bogdan [553]

Answer:

Step-by-step explanation:

6 0

2 years ago

please show on graph (with x and y coordinates) state where the function x^4-36x^2 is non-negative, increasing, concave up

babunello [35]

Answer:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

Step-by-step explanation:

For this case we have the following function:

$y= x^4 -36x^2$

We can find the first derivate and we got:

$y' = 4x^3 -72x$

In order to find the concavity we can find the second derivate and we got:

$y'' = 12x^2 -72$

We can set up this derivate equal to 0 and we got:

$y'' =12x^2 -72=0$

And solving we got:

$x=\pm \sqrt{\frac{72}{12}} =\pm \sqrt{6}$

We can find the sings of the second derivate on the following intervals:

$(-\infty$ Concave up

$x=-\sqrt{6}, y =-180$ inflection point

$(-\sqrt{6}$ Concave down

$x=\sqrt{6}, y=-180$ inflection point

$(\sqrt{6}$ Concave up

8 0

3 years ago

A) 5√160=

drek231 [11]

Answer:

a) 20 $\sqrt{35}$

b) 7 $\sqrt{5}$

c) 18 $\sqrt{2}$

d) 5 $\sqrt{2}$

e) 36 $\sqrt{3}$

f) 72

g) 10 $\sqrt{3}$

Step-by-step explanation:

8 0

3 years ago