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alukav5142 [94]

3 years ago

9

Can somebody help plz it’s due soon?

1 answer:

Snezhnost [94]3 years ago

8 0

The answer is 7/18, basically the amount of people in favour over the Amon t of people in total :)

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6x + 5y =20 solve for y step by step

Marina CMI [18]

Answer:

Move all terms that don't contain y to the right side and solve.y=4−6x/5

Step-by-step explanation:

4 0

3 years ago

Aya and Kendra want to estimate the height of a tree. On a sunny day, Aya measures Kendra's shadow as 3 meters long, and Kendra

densk [106]

Answer:

tree=4.5 meters tall

Step-by-step explanation:

1.5*3=4.5

6 0

3 years ago

Read 2 more answers

Select all the correct locations on the table.

AlladinOne [14]

Average rate of change: r=[f(b)-f(a)]/(b-a)

r=-60→[f(b)-f(a)]/(b-a)=-60

b=5; f(b)=-213; a=1; f(a)=27
(-213-27)/(5-1)=(-240)/4=-60

Answer: The <span>two points in the table which create an interval with an average rate of change of -60 are:
x f(x)
1 27
5 -213</span>

7 0

4 years ago

Read 2 more answers

You deposit $1500 in an account that pays 3% annual interest. Find the balance after 1 year if the interest is compounded monthl

erica [24]

Answer:

I believe the balance would be $1,545.00

7 0

3 years ago

Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000

zvonat [6]

Answer:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

$A = \int\limits^t_ {1} \,{13\cdot x^{3}} dx$

$A = 13 \int\limits^t_1 {x^{3}} \, dx$

$A = \frac{13}{4}\cdot (t^{4}-1)$

Evaluated areas are presented below:

t = 10

$A = 32496.75$

t = 100

$A = 324999996.8$

t = 1000

$A=3.25\times 10^{12}$

8 0

4 years ago