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Nikitich [7]
3 years ago
9

I need help with this math problem please

Mathematics
2 answers:
Gekata [30.6K]3 years ago
8 0

Answer:

C)  3(x+7)²

Step-by-step explanation:

MAVERICK [17]3 years ago
5 0

Answer:

A) (3x + 21)(x + 7)

Step-by-step explanation:

If we look at the equation we can see that it is a quadratic equation, therefore we can factor it in the following way...

3x^{2} + 42x + 147 = 3x^{2} + 21x + 21x + 147 = 3x(x + 7) + 21(x + 7) = (3x + 21)(x + 7)

Therefore the answer is A)

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A parabola with no real zeros, a negative leading coefficient, and an odd y-intercept.<br> pls help!
pishuonlain [190]

Answer:

Step-by-step explanation:

A parabolic graph with no real zeros never touches or crosses the x-axis.  

If the leading coefficient is negative, that tells us that the parabola opens down (and, in this case, that the entire graph is below the x-axis, because there are no real zeros.

If the y-intercept is odd, then the constant term, c, in ax^2 + bx + c, must be a negative, odd integer.

Suppose we say that the vertex of a particular parabola that is described by the above is (-2, -1) and that the y-intercept is -3.  (Note:  this is strictly an example.)  Then the vertex equation of this parabola is obtained from the general vertex equation of a parabola,

y = a(x - h)^2 + k.  Here h = -2 and k = -1, and so the particular parabola is

y = -a(x + 2)^2 - 1, where a is a constant and -a is negative.

In general form, this would be y = -a(x^2 + 4x + 4) - 1, or

                                                   y = -ax^2 - 4ax - 4a -1

and the constant terem (-4a -1) must be an odd negative integer

This is only one of an infinite number of possible equations for the parabola described above.

5 0
3 years ago
Read 2 more answers
A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl
Andrew [12]

Answer: \dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9} or  \dfrac{228}{91885} .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = ^{52}C_9

Now , the combination of 9 cards such that exactly 6 of them are  face cards =  ^{12}C_{6}\times^{40}C_3

Now , the probability that the hand contains exactly 6 face cards will be :-

\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}

=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}

Hence, the probability that the hand contains exactly 6 face cards. is  \dfrac{228}{91885} .

6 0
3 years ago
Please help me find the answer​
Ksivusya [100]

Answer:

-4 1/4

Step-by-step explanation:

-7 3/4 + 3 1/2 = -4 1/4

8 0
3 years ago
GEOMETRY NEED HELP AS SOON AS POSSIBLE
Aneli [31]

Answer:

BAC=15

Step-by-step explanation:

angle BOA= 180-30= 150

triangle BAO is   isosceles because it has two equal sides, radii of a circumference so the angles ABO=BAO=(180-150)/2=15

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3 years ago
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Number 8 please! It's urgent
kykrilka [37]
T chart but thats all i can think of
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