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jeyben [28]
3 years ago
9

A cylinder has a base diameter of 6 feet and a height of 2 feet. What is its volume

Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

56.55

Step-by-step explanation:

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PLEASE HELP WILL GIVE BRAINLIST
Neko [114]

Answer:

b= -1/4

Step-by-step explanation:

I just get it on a work a day ago good luck

4 0
3 years ago
1/4 x 6 + 3 x 7 anybody know the answer
marta [7]

Answer:

22.5 or 22 1/20

Step-by-step explanation:

1/4 x 6 = 1.5    7 x 3 = 21  21 + 1.5 = 22.5

8 0
3 years ago
What is the value of f(-2)?
Naddika [18.5K]
The answer to f(-2) is -3
4 0
3 years ago
Do you know how to do this question
Sever21 [200]

Percentage of the area shaded = 55%

Solution:

Perimeter of the square = 40 cm

Each side of the square = \frac{40}{4} = 10 cm

Area of the square = \text{side}^2

                               = 10²

                               = 100

Total area of the square = 100 cm²

The unshaded portion is two triangles.

Base of the smaller triangle = 10 cm – 7 cm = 3 cm

Height of the smaller triangle = 10 cm

Area of the smaller triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                              $=\frac{1}{2}\times 3\times 10

Area of the smaller triangle = 15 cm²

Base of the larger triangle = 10 cm – 4 cm = 6 cm

Height of the larger triangle = 10 cm

Area of the larger triangle = \frac{1}{2}\times \text{base}\times \text{height}

                                              $=\frac{1}{2}\times 6\times 10

Area of the larger triangle = 30 cm²

Area of the shaded portion = Area of the square – Area of the smaller

                                                   triangle – Area of the larger triangle

                                              = 100 cm² – 15 cm² – 30 cm²

Area of the shaded portion = 55 cm²

Percentage of the area shaded = \frac{\text{Area of the shaded portion}}{\text{Total area of the square}}\times100\%

                                                    $=\frac{55}{100}\times100\%

Percentage of the area shaded = 55%

8 0
3 years ago
a. Calculate the volume of the solid of revolution created by rotating the curve y = 3 + 3 exp(-5 x) about the x-axis, for x bet
miskamm [114]

Answer:

A) The volume of solid is 18π cubic unit.

B) The volume of sphere is \dfrac{4}{3}\pi r^3

    a = -r , b = r , f(x)=\sqrt{r^2-x^2} and V=\dfrac{4}{3}\pi r^3

Solution A)

The given curve, y=3+3e^{-5x} rotate about x-axis between 2 to 4.

Please find attachment for solid figure or rotation.

Using disk method to find the volume rotation about x-axis

V=\int_a^b\pi R^2dx  

where, a = 2, b= 4 , R=y=3+3e^{-5x} and dx is thickness of disk.

V=\int_2^4\pi (3+3e^{-5x})^2dx

V=9\pi\int_2^4(1+e^{-10x}+2e^{-5x})dx

V=9\pi(x-\dfrac{1}{10}e^{-10x}-\dfrac{2}{5}e^{-5x})|_2^4)

V=9\pi(4-\dfrac{1}{10}e^{-40}-\dfrac{2}{5}e^{-20}-2+\dfrac{1}{10}e^{-20}-\dfrac{2}{5}e^{-10}))

V=9\pi (2-0)

V=18\pi

Hence, the volume of solid is 18π cubic unit

Solution B)

The equation of circle of radius r and centered at origin (0,0).

x^2+y^2=r^2

y=\sqrt{r^2-x^2}

The solid form is sphere of radius r.

Using disk method, to find volume of solid

V=\int_a^b\pi R^2dx  

where, a = -r, b = r , R=y=\sqrt{r^2-x^2} and dx is thickness of disk.

V=\int_{-r}^r\pi (r^2-x^2)dx

V=\pi(r^2x-\dfrac{x^3}{3})|_{-r}^r

V=\pi(2r^3-\dfrac{2r^3}{3})

V=\dfrac{4}{3}\pi r^3

Hence, the volume of sphere is \dfrac{4}{3}\pi r^3

4 0
3 years ago
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