Short leg = x-6m
Longer leg =x
Hypotenuse = x+6m
x² + (x-6)² =(x+6)²
x² + x²-12x+36 = x²+12x+36
2x²-12x+36= x² +12x+36
2x²-12x+36-36= x² +12x+36-36
2x² - 12x-12x = x²+12x-12x
2x² -24x-x² = x²-x²
x² -24x = 0
x(x-24)=0
x = 24
Short leg = 24-6m = 18
Longer leg =24
Hypotenuse = 24+6m=30
Check
a² + b² = c²
18² +24² =30²
324 +576 = 900
900=900
Answer:
10,350$
Step-by-step explanation:
2,300÷2=1,150
1,150×2=2,300
1,150×9=10,350
A represents the speed of the aircraft.
b represents the speed of the bus.
a=2b-5
114/b=218/a
Substitution method
114/b=218/(2b-5)
(2b-5)*(114/b)= 218
(228b-570)/b = 218
228b-570= 218b
228b-218b=570
10b= 570
b=57
Plug the value of b into one of the original equations.
a=2(57)-5
a=114-5
a=109
Final answer:
Average speed of plane= 109
Average speed of bus= 57
Answer:
x ≤ 3
Step-by-step explanation:
The expression inside the radical ≥ 0, thus
solve
9 - 3x ≥ 0 ( subtract 9 from both sides )
- 3x ≥ - 9
Divide both sides by - 3, reversing the symol as a result of dividing by a negative quantity
x ≤ 3
Any value of x less than or equal to 3 ensures 
is real
