Use the formula d = ( r − c ) t to find c if d = 30 , r = 12 , and t = 5 . C=

What is pi at its longest decimal?

victus00 [196]

Answer : Pi is infinite

If you want longest decimal that would take a very very long time use 3.14

Step-by-step explanation:

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=Y%3D%5Cfrac%7B-2%7D%7Bx%7D%2B4" id="TexFormula1" title="Y=\frac{-2}{x}+4" alt="Y=\frac{-2}{x}+

Studentka2010 [4]

Part A: Vertical asymptote is $x=0$

Part B: Domain is $\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)$

Part C: Horizontal asymptote is $y=4$

Part D: Range is $\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)$

Explanation:

Part A: We need to determine the vertical asymptote

The vertical asymptote of a function can be determined by equating the denominator equal to zero.

Thus, we have,

$x=0$

Hence, the vertical asymptote is $x=0$

Part B: We need to determine the domain

The domain of the function is the set of all independent x - values for which the function is real and well defined.

Let us take the denominator and equate to zero.

Hence, we have, $x=0$

Therefore, the function is undefined at the point $x=0$

Thus, the domain of the function is $\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)$

Part C: We need to determine the horizontal asymptote

The horizontal asymptote of the function can be determined by dividing the leading coefficient of the numerator by leading coefficient of the denominator.

Thus, we have, $y=4$

Hence, the horizontal asymptote of the function is $y=4$

Part D: We need to determine the range

The range of the function is the set of all dependent y -values of the function.

In other words, the range of the function can be determined by substituting the values for x.

Thus, we have,

$\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)$

Therefore, the range of the function is $\left(-\infty \:,\:4\right)\cup \left(4,\:\infty \:\right)$

6 0

3 years ago

Rowena used small wooden cubes to measure the length of her foot and her hand. Her foot was 22 cubes long and her had was 15 cub

Sonja [21]

A. Or B.

I picked this in one of my questions and I don’t remember which specific one but the one or other should be correct.

5 0

3 years ago

Read 2 more answers

How many miles per hour is this? (one furlong is 18 mile, and a fortnight is 14 days. a furlong originally referred to the lengt

WITCHER [35]

the complete question is

While driving in an exotic foreign land you see a speed limit sign on a highway that reads 180,000 furlongs per fortnight. How many miles per hour is this? (One furlong is 1/8 mile, and a fortnight is 14 days. A furlong originally referred to the length of a plowed furrow.)

Step 1

convert (furlongs per fortnight) to (miles per fortnight)

180,000 furlongs per fortnight=180,000*(1/8)=22,500 miles per fortnight

Step 2

convert miles per fortnight to miles per hour

1 day=24 hour

14 day=24*14=336 hours

22,500 miles per fortnight=22,500/336=66.96 mph

therefore

the answer is

66.96 mph

7 0

4 years ago

The J.R. Ryland Computer Company is considering a plant expansion to enable the company to begin production of a new computer pr

Solnce55 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

Medium-Scale Large-Scale

Expansion Profit Expansion Profit

x f(x) y f(y)

Low 50 0.2 0 0.2

Demand Medium 150 0.5 100 0.5

High 200 0.3 300 0.3

a. Compute the expected value for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of maximizing the expected profit?

Expected value for medium scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(50 * 0.2) + (150 * 0.5) + (200 * 0.3)]

= 145

Expected value for Large scale expansion profit :

Expected value (E) = Σ(X) * f(x)

Σ[(0 * 0.2) + (100 * 0.5) + (300 * 0.3)]

= 140

Medium scale expansion profit is preferred as it has the highest expected value.

b. Compute the variance for the profit associated with the two expansion alternatives.

Which decision is preferred for the objective of minimizing the risk or uncertainty?

Variance (V) = Σ(X - E)² * f(x):

Variance for medium scale expansion profit :

V = [((50-145)^2 * 0.2) + ((150-145)^2 * 0.5) + ((200-145)^2 * 0.3) = 2725

Variance for Large scale expansion profit :

V = [((0-140)^2 * 0.2) + ((100-140)^2 * 0.5) + ((300-140)^2 * 0.3) = 12400

Smaller variance is required to minimize risk, Hence, choose the medium scale expansion profit.

3 0

3 years ago