The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Your answer in cm would be 5,200,000.
As 1km=100,000 cm
Answer:
Correct to 1dp
127.3 cm = 127.0 cm
86.5 cm = 87.0 cm
Upper limits:
127.0 cm = 127.05 cm
87.0 cm = 87.05 cm
Lower Limits:
127.0 cm = 126.95 cm
87.0 cm = 86.95 cm
upper limit of perimeter of rectangle:
P = 2(l+w)
= 2(127.05 + 87.05)
= 2(214.1)
= 428.2 cm
lower limit of perimeter of rectangle:
P = 2(l+w)
= 2(126.95 + 86.95)
= 2(213.9)
= 427.8 cm
therefore;

Answer:
B
Step-by-step explanation:
The best - well, only way- is to check a few points.
Namely -1 (unless your eyesight is really poor!), 0, 1, 2, and 3.

Now you can mark all these points in each graph (well, you could if they were on paper and not on a screen) and see which one of the lines passes through all of them. Spoiler alert, it's the B graph.
A represents
, B is the one you want, C is
and D looks like 
Answer:
Step-by-step explanation:equivalent expressions