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Ray Of Light [21]

3 years ago

10

Understanding the Number of Solutions Miriam works more than 40 hours a Find the solutions of the inequality and complete the st

atements. week. h> 40 The solutions of the inequality include all numbers + 0 20 40 60 80 solutions There are of the inequality. ✓ Done Intro

2 answers:

Brums [2.3K]3 years ago

7 0

Answer:

Miriam works more than 40 hours a week.

h > 40

A number line going from 0 to 80.

Find the solutions of the inequality and complete the statements.

The solutions of the inequality include all numbers

✔ greater than 40

.

There are

✔ an infinite number of

solutions of the inequality.

Step-by-step explanation:

arsen [322]3 years ago

6 0

Answer:

The solutions of the inequality include all numbers greater than 40.

There are an infinite number of the inequality.

Step-by-step explanation:

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[Quick Answer Needed] Which of the following shows the extraneous solution to the logarithmic equation?

Nitella [24]

Answer:

C

Step-by-step explanation:

Given the logarithmic equation

$\log_4x+\log_4(x-3)=\log_4(-7x+21)$

First, notice that

$x>0\\ \\x-3>0\Rightarrow x>3\\ \\-7x+21>0\Rightarrow 7x$

So, there is no possible solutions, all possible solutions will be extraneous.

Solve the equation:

$\log_4x+\log_4(x-3)=\log_4x(x-3),$

then

$\log_4x(x-3)=\log_4(-7x+21)\\ \\x(x-3)=-7x+21\\ \\x^2-3x+7x-21=0\\ \\x^2+4x-21=0\\ \\D=4^2-4\cdot 1\cdot (-21)=16+84=100\\ \\x_{1,2}=\dfrac{-4\pm 10}{2}=-7,\ 3$

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3 years ago

Andrea, Justin, and Virginia went to an office supply store. Andrea bought 6 pencils, 7 markers, and 8 erasers. Her total was $1

olga2289 [7]

Answer:

$x=0.25\,,\,y=1.75\,,\,z=0.25$

Step-by-step explanation:

Let $x,y,z$ denotes number of pencils, markers, erasers respectively.

For Andrea:

$6x+7y+8z=15.75\,\,\,(i)$

For Justin:

$6x+8y+5z=16.75\,\,\,(ii)$

For Virginia:

$5x+5y+7z=11.75\,\,\,(iii)$

On subtracting equations (i) and (ii), we get

$(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z$

Put $y=1+3z$ in equation (i)

$6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)$

Put $y=1+3z$ in equation (iii)

$5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)$

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

$5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25$

Put $z=0.25$ in equation $y=1+3z$

$y=1+3(0.25)=1.75$

Put $y=1.75\,,\,z=0.25$ in equation (i)

$6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25$

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