Question

Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.10 significance level to test for a difference between the measurements from the two arms. What can be​ concluded?

Answer 1

Answer:

WE reject the Null and conclude that significant difference exists

Step-by-step explanation:

Given the data :

Right arm Left Arm

145 173

142 163

116 182

133 148

134 149

The difference, d = Right arm - Left arm

d = -28, -21, -66, -15, -15

The hypothesis ;

H0 : μd = 0

H0 : μd ≠ 0

The test statistic :

T = dbar / (Sd/√n)

dbar = Σd / n = - 145 / 5 = - 29

Sample standard deviation, Sd = 21.366 (Using calculator)

Test statistic = - 29 / (21.366/√5)

Test statistic = - 3.035

Significance level, α = 0.1

α = 0.1 ; df = 5 - 1 = 4

Pvalue(-3.035, 4) = 0.0386

Since Pvalue < α ; WE reject the Null and conclude that significant difference exists