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Oksanka [162]
3 years ago
11

Show the different measuring instruments to be used in the economic/business system of the new civilization.

Mathematics
1 answer:
melomori [17]3 years ago
6 0

Answer:

The different measuring instruments to be used in the economic/business system of the new civilization is discussed below in detail.

Step-by-step explanation:

Economics is the research of how people allocate limited resources for generation, circulation, and consumption, both personally and collectively.

Two significant types of economics are microeconomics, which concentrates on the performance of individual customers and generators, and macroeconomics, which measures overall economies on a local, nationwide, or global scale.

Economics is especially concerned with performance in generation and exchange and practices models and opinions to assume how to generate incentives and procedures that will maximize productivity.

Economists formulate and announce numerous economic symbols, such as the Consumer Price Index (CPI). and gross domestic product (GDP).

Capitalism, communism, and socialism are examples of economic systems.

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Last year, Kelly's Candies sold 425,524,812 candy bars. Chester's Chocolates sold 425,520,736 candy bars. Which company sold mor
stepladder [879]
Kelly's Candies because 425,524,812 is bigger that 425,520,736
3 0
4 years ago
Read 2 more answers
est the hypothesis using the​ P-value approach. Be sure to verify the requirements of the test. Upper H 0 : p equals 0.89 versus
hichkok12 [17]

Answer:

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

The requirements for the test are satisfief.

n(1-p)=70>10

Step-by-step explanation:

This is a hypothesis test for a proportion.

There are 3 requirements to have a valid test of proportion: random sample, independence and normal.

For the first two (random and independent sample) we don't have details, but we assume the sampling has been random.

The latter can be verified by calculating np and n(1-p):

np=430>10\\\\n(1-p)=70>10

Both are bigger than 10, so the normal approximation can be considered appropiate.

The claim is that the population proportion significantly differs from 0.89.

Then, the null and alternative hypothesis are:

H_0: \pi=0.89\\\\H_a:\pi\neq 0.89

The significance level is 0.01.

The sample has a size n=500.

The sample proportion is p=0.86.

p=X/n=430/500=0.86

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.89*0.11}{500}}\\\\\\ \sigma_p=\sqrt{0.000196}=0.014

Then, we can calculate the z-statistic as:

z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.86-0.89+0.5/500}{0.014}=\dfrac{-0.029}{0.014}=-2.072

This test is a two-tailed test, so the P-value for this test is calculated as:

\text{P-value}=2\cdot P(z

As the P-value (0.038) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the population proportion significantly differs from 0.89.

6 0
3 years ago
Find the x-intercepts and y-intercept of the following function (x−5)(x−3)(4x+8)
Sergio [31]
X-intercepts:
(x-5)(x-3)(4x+8)=0

x-5=0 x-3=0 4x+8=0
x=5 x=3 x=-8/4
x=-2

Y-intercept:
sub x=0
(0-5)(0-3)(4(0)+8)=y

(-5)(-3)(8)=y

y = 120
5 0
3 years ago
Simplify (12-6i) - (-3 - 8i)
mestny [16]
(12-6i)-(-3-8i). First you have to combine like terms, to do that remove the parenthesis: 12-6i-3+8i (because there is a - in front of the second parentheses the signs inside change). Now combine like terms: 9+2i. So your answer is 9+2i :)
6 0
3 years ago
PLEASE HELP QUICK!! Repost because typos | 100 POINTS
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Well you have to first look at the chart to see if it fits what Ariel claimed.

There is actually a higher percent of students with no siblings that have pets if you look at the total for students with no siblings. If you look at the number though 45>39. Also her claim is not justified because the percentage is lower for students with siblings. Thanks for the 50 points ;) If you have any questions just ask

4 0
3 years ago
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