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Katen [24]
3 years ago
7

What is the slope of a line perpendicular to the line y = 1/5x - 3

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

-5

Step-by-step explanation:

Perpendicular lines have negative reciprocal slopes.

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Pls help I’ll addd extra points
Irina-Kira [14]

Answer: 3/5

Step-by-step explanation:6/10 6 divide by 2 and 10 divide by 2

hoped this helped:)

3 0
3 years ago
Read 2 more answers
Can someone please help me with number 2?I don't know what I did wrong.​
Dmitry [639]

Part A

Let's say point P is the starting point and point Q is the endpoint

x = one-way distance from P to Q, and vice versa

The goal is to find x, then compute 2x to find the round trip distance traveled.

We'll use this idea

distance = rate*time

which solves to

time = distance/rate

So when going from P to Q, the driver is going 70 mph and travels x miles

So the driver does this for distance/time = x/70 hours.

When going back, the driver slows down to 55 mph so the time taken here is x/55 hours.

The total time values add to x/70 + x/55 hours

Set this equal to the total driving time of 7 hours and solve for x

x/70 + x/55 = 7

70*55*(x/70 + x/55) = 70*55*7

70*55*(x/70) + 70*55*(x/55) = 26,950

55x + 70x = 26,950

125x = 26,950

x = (26,950)/125

x = 215.6 which is the one-way distance in miles

which then means,

2x = 2*215.6 = 431.2

Therefore, the total distance traveled is 431.2 miles

<h3>Answer: 431.2 miles</h3>

=========================================================

Part B

To find the duration of each trip, we simply need to evaluate x/70 and x/55. Those are the durations when going 70 mph and 55 mph respectively. These durations are measured in hours.

x/70 = (215.6)/70 = 3.08

x/55 = (215.6)/55 = 3.92

Note how 3.08+3.92 = 7 to help verify the answers.

<h3>Answers:</h3>
  • When going 70 mph, it takes about 3.08 hours
  • When going 55 mph, it takes about 3.92 hours
6 0
3 years ago
Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?
Tema [17]

Answer:

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Step-by-step explanation:

We are given that

f(x)=tan(x)-\frac{2}{x}

g(x)=x^2+8

We have to find f(x)\times g(y)

To find the value of f(x)\times g(y) we will multiply f(x) by g(y)

g(y)=y^2+8

Now,

f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)

f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

Hence,

f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}

5 0
3 years ago
Which statement about these two sandboxes is true?
adell [148]
A would be the answer
5 0
3 years ago
Effectuer les calculs suivants en les décomposant.
marishachu [46]

Answer:

A=24

B=20

C=10

please mark me as brainalist

6 0
2 years ago
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