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Anarel [89]
3 years ago
10

Given the parent functions f(x) = log10 x and g(x) = 3x − 1, what is f(x) • g(x)?

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0
We are given with two functions f(x) = log10 x and g(x) = 3x − 1 and is asked for the product of the two functions expressed as f(x) • g(x). The answer then is simply the product of the two functions, that is log x * (3x - 1). log 10 x is equal to log x. 
Molodets [167]3 years ago
6 0

Answer:

\log_{10}x \cdot (3x-1) or

3x \log_{10} x -\log_{10} x

Step-by-step explanation:

Given the parent function:

f(x) =\log_{10} x and g(x)=3x-1

we have to find f(x) \cdot g(x)

f(x) \cdot g(x)

⇒(\log_{10}x) \cdot (3x-1)

⇒\log_{10}x \cdot (3x-1)

or

we can write this as:

3x \log_{10} x -\log_{10} x

Therefore, the result of f(x) \cdot g(x) we get, \log_{10}x \cdot (3x-1) or 3x \log_{10} x -\log_{10} x

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Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).
zzz [600]

Answer:

F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

Step-by-step explanation:

We have given F(S)=\frac{7e^{-7s}}{s^2-49}

Now  F(S)=e^{-7s}G(s)

Here G(S)=\frac{7}{S^2-49}

Now first find the Laplace inverse of G(S)

Using partial fraction

\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}

7=A(S-7)+B(S+7)

On comparing the coefficient

A=\frac{1}{2}  and B=\frac{-1}{2}  

On putting the value of A and B  

G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}

Taking inverse Laplace

G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}

Now in G(s) there is onether term e^{-7s}

So F(t)=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}

6 0
3 years ago
The number of bacteria growing in an incubation culture increases with time according to n left parenthesis t right parenthesis
Anon25 [30]
For this case we have the following function:
 n (t) = 2400 * (5) ^ t 
 For n (t) = 60000 we have:
 60000 = 2400 * (5) ^ t
 We clear the value of t.
 For this we use the logarithm:
 (5) ^ t = 60000/2400
 log5 ((5) ^ t) = log5 (60000/2400)
 t = log5 (60000/2400)
 t = 2 days
 Answer:
 
the number of bacteria in the culture will be 60 comma 000 after:
 
t = 2 days
5 0
3 years ago
Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Show the correct substitution of the values
Grace [21]
I hope this helps you

5 0
3 years ago
Pls explain How do do all of these and say answers
lyudmila [28]

Answer:

QUESTION ONE-

Cross multiply:

5 * 15 = 12 * y

Simplifying

5 * 15 = 12 * y

Multiply 5 * 15

75 = 12 * y

Solving

75 = 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.

75 + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0

75 + -12y = 0

Add '-75' to each side of the equation.

75 + -75 + -12y = 0 + -75

Combine like terms: 75 + -75 = 0

0 + -12y = 0 + -75

-12y = 0 + -75

Combine like terms: 0 + -75 = -75

-12y = -75

Divide each side by '-12'.

y = 6.25

Simplifying

y = 6.25

QUESTION TWO-

Cross multiply:

8 * w = 20 * 6

Simplifying

8 * w = 20 * 6

Multiply 20 * 6

8w = 120

Solving

8w = 120

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Divide each side by '8'.

w = 15

Simplifying

w = 15

QUESTION 3-

Cross multiply:

s + 1 * 8 = 4 * 4

Simplifying

s + 1 * 8 = 4 * 4

Reorder the terms:

1 + s * 8 = 4 * 4

Reorder the terms for easier multiplication:

8 * 1 + s = 4 * 4

1 * 8 + s * 8 = 4 * 4

8 + 8s = 4 * 4

Multiply 4 * 4

8 + 8s = 16

Solving

8 + 8s = 16

Solving for variable 's'.

Move all terms containing s to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 8s = 16 + -8

Combine like terms: 8 + -8 = 0

0 + 8s = 16 + -8

8s = 16 + -8

Combine like terms: 16 + -8 = 8

8s = 8

Divide each side by '8'.

s = 1

Simplifying

s = 1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which property is illurstaed by this problem. (6.3x)y=6.3(xy)
Sergio [31]
Its the identity property

6 0
3 years ago
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