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3 years ago

10

I need to find the slope for these lines please help

1 answer:

geniusboy [140]3 years ago

8 0

Answer:

-3/1 for both

Step-by-step explanation:

the slope of a parallel line is the same

pls mark brainliest

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Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Is this possible if he invests with a rate

Juli2301 [7.4K]

Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Question: Is this possible if he invests with a rate of return of 6%?We'll we are not sure with the answer unless we solve it. So let's start solving.=> 6% = 6% / 100% = 0.06Now, we have the value of 6% that will be multiplied with the amount to identify his annual interest rate:=> $4,200 * 0.06 = 252 dollars is his annual interest rateLet's multiply this for 4 years=> 252 dollars * 4 = 1008 dollarsThen, let's sum up:<span>=> $4,200 + 1008 dollars = 5 208 dollars.</span>

5 0

3 years ago

Read 2 more answers

The measure of an angle is 83.4°. What is the measure of its supplementary angle?

Natalija [7]

Answer:

The supplementary angle is 96.6.

Step-by-step explanation:

Complementary angles make up to 90 degrees, but since this is a supplementary angle, it'll make up to 180 degrees. From there, you subtract 180-83.4 to get 96.6 degrees.

5 0

3 years ago

The object on the right is made from a square-based pyramid joined to a cuboid.

spayn [35]

Answer:

Density of steel = 80.73 gm/ $cm^3$

Step-by-step explanation:

The figure is made up of cuboid and square pyramid.

Height of cuboid, h = 9 cm

Length of cuboid, l = 6 cm

Width of cuboid, w = 6 cm

Volume of cuboid is given by the formula:

$V_{Cuboid} = l \times w \times h$

$V_{Cuboid} = 6 \times 6 \times 9\\\Rightarrow V_{Cuboid} = 324\ cm^3$

Density of Wood , $D_{Cuboid}$ = 0.68g/ $cm^3$

We know that formula of Density is:

$Density = \dfrac{Weight}{Volume}$

$D_{Cuboid} = \dfrac{W_{Cuboid}}{V_{Cuboid}}\\\Rightarrow W_{Cuboid} = V_{Cuboid} \times D_{Cuboid}$

Putting the values:

$W_{Cuboid} = 324 \times 0.68 = 220.32\ gm$

Total weight = $W_{Cuboid} + W_{Pyramid}$

970 = 220.32 $+ W_{Pyramid}$

$W_{Pyramid}$ = 749.68 gm

Volume of pyramid is given as:

$V_{Pyramid}= \dfrac{1}{3} \times \text{Area of Base} \times \text{Vertical Height}$

Base is a square with side 6 cm

$V_{Pyramid}= \dfrac{1}{3} \times 6 \times 6 \times (17 -9)\\V_{Pyramid}= 96\ cm^3$

Density of Steel/Pyramid:

$D_{Pyramid} = \dfrac{W_{Pyramid}}{V_{Pyramid}}\\\Rightarrow D_{Pyramid} = \dfrac{749.68}{96}\\\Rightarrow D_{Pyramid} = 80.73\ gm/cm^3$

5 0

4 years ago

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

7 0

3 years ago

Choose the answer based on the most efficient method as presented in the lesson.

natita [175]

The next step is to add 9

7 0

4 years ago

Read 2 more answers