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Alekssandra [29.7K]
3 years ago
9

Quadrilateral PQRS was translated 5 units to the right and 3 units up to create quadrilateral P 'Q 'R 'S '. Which rule describes

this transformation?
A (x,y) - (x = 3, y + 5)
B (x,y) - (x - 5,y-3)
C (x,y) - (x - 3, y - 5)
D (x,y) - (x + 5,y + 3)
Mathematics
1 answer:
Wittaler [7]3 years ago
6 0

Answer: did you get the answer

Step-by-step explanation: pleasee

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How do you do this?
ELEN [110]
Use the Pythagorean Theorem: a² + b² = c².

a and b are the legs of the right triangle, and c is the hypotenuse.

2) 5² + b² = 6²
    25 + b² = 36
    b² = 11
    b = 3.3 cm

3) 7² + b² = 8²
    49 + b² = 64
    b² = 15
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4) a² + 5² = 13²
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     a² = 144
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3 years ago
For i≥1 , let Xi∼G1/2 be distributed Geometrically with parameter 1/2 . Define Yn=1n−−√∑i=1n(Xi−2) Approximate P(−1≤Yn≤2) with l
murzikaleks [220]

Answer:

The answer is "0.68".

Step-by-step explanation:

Given value:

X_i \sim \frac{G_1}{2}

E(X_i)=2 \\

Var (X_i)= \frac{1- \frac{1}{2}}{(\frac{1}{2})^2}\\

             = \frac{ \frac{2-1}{2}}{\frac{1}{4}}\\\\= \frac{ \frac{1}{2}}{\frac{1}{4}}\\\\= \frac{1}{2} \times \frac{4}{1}\\\\= \frac{4}{2}\\\\=2

Now we calculate the \bar X \sim N(2, \sqrt{\frac{2}{n}})\\

\to \frac{\bar X - 2}{\sqrt{\frac{2}{n}}}  \sim  N(0, 1)\\

\to \sum^n_{i=1}  \frac{X_i - 2}{n}  \times\sqrt{\frac{n}{2}}}  \sim  N(0, 1)\\\\\to  \sum^n_{i=1}  \frac{X_i - 2}{\sqrt{2n}}  \sim  N(0, 1)\\

\to Z_n = \frac{1}{\sqrt{n}} \sum^n_{i=1} (X_i -2) \sim N(0, 2)\\

\to P(-1 \leq X_n \leq 2)  = P(Z_n \leq Z) -P(Z_n \leq -1) \\\\

                               = 0.92 -0.24\\\\= 0.68

6 0
3 years ago
Bernice bought 3/1/2 pound of apples and 5/2/3 pounds of oranges and 11/12 pounds of bananas what was the total weight of fruit
torisob [31]

10 1/12

3 1/2 + 5 2/3 + 11/12 = 10 1/12

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57 x .02 will get the right answr
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<span>7 is divisible by 7 and not by 14. </span>
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