If you've started pre-calculus, then you know that the derivative of h(t)
is zero where h(t) is maximum.
The derivative is h'(t) = -32 t + 96 .
At the maximum ... h'(t) = 0
32 t = 96 sec
t = 3 sec .
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If you haven't had any calculus yet, then you don't know how to
take a derivative, and you don't know what it's good for anyway.
In that case, the question GIVES you the maximum height.
Just write it in place of h(t), then solve the quadratic equation
and find out what 't' must be at that height.
150 ft = -16 t² + 96 t + 6
Subtract 150ft from each side: -16t² + 96t - 144 = 0 .
Before you attack that, you can divide each side by -16,
making it a lot easier to handle:
t² - 6t + 9 = 0
I'm sure you can run with that equation now and solve it.
The solution is the time after launch when the object reaches 150 ft.
It's 3 seconds.
(Funny how the two widely different methods lead to the same answer.)
The answer is from AL2006
Answer:
A≈345.58cm²
Step-by-step explanation:
Radius= 5cm and the Height= 6cm
Answer:
the lengths of the sides of the yard.
Step-by-step explanation:
I think the answer is True
The formula for the future value A, given annual interest rate r, number of years t, and deposit amount P can be written as
... A = P(1 +r/12)((1+r/12)^(12t) -1)/(r/12)
Filling in the given numbers, you have
... A = 200(1+.0275/12)((1+.0275/12)^(12·39) -1)/(.0275/12) ≈ 167,868.30
The appropriate choice is $167,868.30.
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The formula is the one for the sum of a geometric series. It can be useful to consider the last deposit made as the first term of the series.
