We know that equation of a parabola is given by :-
y = a(x-h)² + k
Where (h,k) is the vertex of parabola and (x,y) is any point on its curve.
Given that vertex of parabola is (3,5) and one point (x,y) is (6,-1).
We can plug the given information in the equation of parabola and solve it for value of 'a' :-
-1 = a(6 - 3)² + 5
-1 = a(3)² + 5
-1 = 9a + 5
9a = -1 -5 = -6
a = 
a = 
is the final answer.
Answer:
3
Step-by-step explanation:
to evaluate substitute x = 4 into the rational expression, that is
= 
= 3
Answer:
f(-5)=240
g(-7)=-33
Step-by-step explanation:
1) f(x)=3x^2 - 3x
f(-5)= 3×(-5)^2 - 3×(-5) = -15^2 + 15= 225 + 15=240
2) g(x)=5x + 2
g(-7)= 5×(-7) + 2= -35+2=-33
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3
2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10
3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
