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taurus [48]
3 years ago
10

Does (2,9) make the inequality y = 4x + 1 true?

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

Brums [2.3K]3 years ago
5 0

Answer:

Yes

Step-by-step explanation:

If you graph it and you go to the point (2,9) then the line will pass it

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What can go into 10.8 and 36
kogti [31]
10.9
35.99999999999999999999999999999999999 (repeating) 
11.1
11.12324343
23.8743894099

Basically any number between 10.8 and 36.
Hope I helped.
7 0
3 years ago
Read 2 more answers
11) 54% of 35 is what?
Verdich [7]

Answer:

18.36

Step-by-step explanation:

g00gle says so

7 0
3 years ago
Read 2 more answers
The fastest man in the world can run 100 metres in 9 seconds how far can He run in 1 minute and 2 seconds
finlep [7]

Answer:

Step-by-step explanation:

Rate per sec = 100 ÷ 9 = 11.111

1 min and 2 sec = 3600 + 2sec = 3602 sec

Metre = 324.21 metre

7 0
3 years ago
If a crew of 4 workers complete the job in 10 hours, how long will it take 5 workers to complete the same job?
Ulleksa [173]
We can solve using proportions
\frac{4}{10}  =  \frac{5}{x}
or 4 works is to 10 hours as 5 workers is to x hours.
to solve we cross multiply to get
4x = 50 \\ x =  \frac{50}{4}
so it will take 5 men 12.5 hours!
6 0
3 years ago
Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 48 day
irina1246 [14]

Answer:

P ( x_bar ≥ 51 ) = 0.0432

Step-by-step explanation:

Solution:-

- The random variable "X" denotes:

                  X : life expectancies of a certain protozoan

- The variable "X" follows normal distribution.

                  X ~ Norm ( 48 , 10.5^2 )

- A sample of n = 36 days was taken.

- The sample is also modeled to be normally distributed:

                  x ~ Norm ( 48 , ( 10.5 / √n)^2 )

- The sample standard deviation s = 10.5 / √n = 10.5 / √36

                                                      s = 1.75

- We are to investigate the the probability of sample mean x_bar ≥ 51 days:

                 P ( x_bar ≥ 51 )

- Standardize the results, evaluate Z-score:

                 P ( Z ≥ ( x_bar - u ) / s ) =  P ( Z ≥ ( 51 - 48 ) / 1.75 )

                 P ( Z ≥ 1.7142 ).

- Use the standardized normal table and evaluate:

                 P ( Z ≥ 1.7142 ) = 0.0432                  

Hence,      P ( x_bar ≥ 51 ) = 0.0432

5 0
3 years ago
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