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Find the moles of Boron and of Chlorine:
Assume there are 100 g of the compound in all
Boron: 9.224% --> .09224 (convert percent to decimals)
.09224*100g = 9.224g Boron (theoretical amt)
9.224g* 1mol/10.81g (molar mass Boron) = .8533 moles Boron
Answer:
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To understand the main idea of an informational text, you should ask yourself
“Does the author include relevant details?”
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“Which facts support the claim?”
“What evidence does the author provide?”
The answer is; the merchant's daughter.
<em>Hope this helped! :)</em>
