Count the number of multiples of 3, 4, and 12 in the range 1-2005:
⌊2005/3⌋ ≈ ⌊668.333⌋ = 668
⌊2005/4⌋ = ⌊501.25⌋ = 501
⌊2005/12⌋ ≈ ⌊167.083⌋ = 167
(⌊<em>x</em>⌋ means the "floor" of <em>x</em>, i.e. the largest integer smaller than <em>x</em>, so ⌊<em>a</em>/<em>b</em>⌋ is what you get when you divide <em>a</em> by <em>b</em> and ignore the remainder)
Then using the inclusion/exclusion principle, there are
668 + 501 - 2•167 = 835
numbers that are multiples of 3 or 4 but not 12. We subtract the number multiples of 12 twice because the sets of multiples of 3 and 4 both contain multiples of 12. Subtracting once removes the multiples of 3 <em>and</em> 4 that occur twice. Subtracting again removes them altogether.
Answer:
:w=1/3(a)
Step-by-step explanation:
w = 1/3 × a
If Lago is 150lb, Jeb's =
1/3 x 150 = 50 lb
If Lago is 60lb, Jeb's =
1/3 x 60 = 20lb
So Sally gets payed <span>$32,448 a year and gets paid the same amount each week. To figure how much she gets payed a week, divide her salary by 52 weeks since there are 52 weeks in a year. Then we divide how much she makes a week by 40 to see how much she gets payed an hour since she works 40 hours each week:
</span><span>32,448/52 = 624
624/40 = 15.6
Sally makes $15.60 an hour.
</span>
Answer:
See explanation
Step-by-step explanation:
Statement Reason
1. the diagram shows segment AC with point B on this segment, then
<u>Segment addition postulate</u>
2. Given 
then
<u>Substitution property</u>
3. Simplify the equation as follows
<u>Combine like terms</u>
4. Subtract 8 from both sides
<u>Subtraction property of equality</u>
5. Divide by 8:
<u>Division property of equality</u>
X= small angle
x+50= larger angle
supplementary angles=180 degrees
x+x+50= 180
combine like terms
2x+50=180
subtract 50
2x= 130
divide by 2
x= 65 degrees for the smaller angle
115 degrees for the larger
hope this helps
