ANSWER:
The surface area of the star is 3.2700 x 
square kilometres.
EXPLANATIONS:
Diameter of the star = 1.8083 x 
Km.
Surface area of the star = 4
Where n is the radius of the star.
So that;
n = 
= 0.90415 x
n = 0.90415 x Km
Thus,
Surface area = 4 x 
= 326994889
Surface area = 3.2700 x 
Therefore, the surface area of the star is 3.2700 x square kilometres.
The quotient is the answer to a division problem.
Answer:
corresponding angles postulate
Step-by-step explanation:
just took the test ;)
H= 2a/a+b woolud be the answer
Answer:
We accept H₀ with the information we have, we can say level of ozone is under the major limit
Step-by-step explanation:
Normal Distribution
population mean = μ₀ = 7.5 ppm
Sample size n = 16 df = n - 1 df = 15
Sample mean = μ = 7.8 ppm
Sample standard deviation = s = 0.8
We want to find out if ozono level, is above normal level that is bigger than 7.5
1.- Hypothesis Test
null hypothesis H₀ μ₀ = 7.5
alternative hypothesis Hₐ μ₀ > 7.5
2.-Significance level α = 0.01 we will develop one tail-test (right)
then for df = 15 and α = 0,01 from t -student table we get
t(c) = 2.624
3.-Compute t(s)
t(s) = ( μ - μ₀ ) / s /√n ⇒ t(s) = ( 7.8 - 7.5 )*4/0.8
t(s) = 0.3*4/0.8
t(s) = 1.5
4.-Compare t(s) and t(c)
t(s) < t(c) 1.5 < 2.64
Then t(s) is inside the acceptance region. We accept H₀
