3 years ago

PLEASE HELP DUE IN TONIGHT!!!

Mathematics

1 answer:

wel3 years ago

4 0

Answer:

(1,2)

Step-by-step explanation:

4×1=4

3×2=6

then add 4+6 to get 10

then you do the same for the bottom so

5×1=5

4×2=8

5+8=13

You might be interested in

The cost of text books for school increases with the average class size identify the independent and dependent quantity in the s

Zinaida [17]

C average class size; cost

3 0

2 years ago

Read 2 more answers

An equilateral triangle has a perimeter of 15x +3. what is the length of each side of the triangle?

xxTIMURxx [149]

The length of each side is 5x + 1

3 0

3 years ago

60 - 3d + 20 - 6 = 4d

iragen [17]

60-3d + 20-6 =4d
74-3d =4d
-3d =4d -74
-7d = -74
D=74/7

4 0

2 years ago

Read 2 more answers

Find the intersection point between the lines of equations:<br><br>2x-y+6=0 and 2x+3y-6=0

Ugo [173]

Step-by-step explanation:

The two equation will intersect each other at the point which will be the solution of the given two equations , and the given equations are ,

$\implies 2x -y +6=0\\\\\implies 2x + 3y -6=0$

On subtracting the given equations we have,

$\implies -y - 3y +6 -(-6) = 0 \\\\\implies -4y = -12 \\\\\implies y = -12/-4\\\\\implies y = 3$

Put this value in any equation , we have ,

$\implies 2x -3 +6 =0\\\\\implies 2x = -3 \\\\\implies x =\dfrac{-3}{2} \\\\\implies x =-1.5$

Hence the lines will Intersect at ,

$\implies\underline{\underline{ Point=(-1.5, 3)}}$

8 0

2 years ago

Read 2 more answers

I need help on how to solve this equation C+(4-3c)-2=0 stp by step

Mumz [18]

Step 1- Simplify brackets
c + 4 - 3c -2 = 0
Step 2- Simplify c + 4 - 3c -2 to -2c + 4 - 2
-2c + 4 - 2 = 0
Step 3- Simplify -2c + 4 - 2 to 2c + 2
-2c + 2 = 0
Step 4- Subtract 2 from both sides
-2c = -2
Step 5- Divide both sides by -2
Answer: c = 1

8 0

2 years ago