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Lilit [14]
3 years ago
14

A wildlife census estimates that the population of endangered deer in the Kashmir Valley has registered an increase. Last year’s

population of Hangul deer was about 1,840 deer. What is the expected female population this year if the increase of the total deer population was about 3% and about 44% of the total deer population are females?
A.810 B.830 C.850 D.870
Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

d

Step-by-step explanation:

You might be interested in
Who is faster?
Kay [80]
Kendra is going faster. You could convert Kendra's measurement to feet per second by doing to following:

0.25 mi/1 min x 5280 ft/1 mi x 1 min/60 sec

Which equals:

(0.25)(5280)ft/60 sec

Simplify, and Kendra's speed is 22 feet per second.

mi= mile(s)
min= minute(s)
ft= feet
sec= second(s)
6 0
3 years ago
There are 416 students who are enrolled in an introductory geology course. if there are seven boys to every six girls, how many
Alenkinab [10]

\text{Let the number of boys be x and number of girls be y.}\\
\\
\text{and there are total 416 students enrolled in the course. so we have}\\
\\
x+y=416 \ \ \ \ \ \ \ \ \ \ ......(i)\\
\\
\text{also given that there are seven boys to every six girls, that is}\\
\\
\frac{x}{y}=\frac{7}{6}

\Rightarrow 6x=7y\\
\\
\Rightarrow y=\frac{6x}{7}\\
\\
\text{substitute this value of y in (i), we get}\\
\\
x+\frac{6x}{7}=416\\
\\
\Rightarrow \frac{7x+6x}{7}=416\\
\\
\Rightarrow \frac{13x}{7}=416\\
\\
\Rightarrow x=\frac{416\times 7}{13}\\
\\
\Rightarrow x=224

Hence the number of boys in the course are: 224

4 0
4 years ago
Find the approximate perimeter of ABC plotted below.
maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}

AB = \sqrt{4 + 4}

AB = \sqrt{16}

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}

BC = \sqrt{25 + 49}

BC = \sqrt{74}

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}

AC = \sqrt{47 + 25}

AC = \sqrt{74}

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0
3 years ago
Please help I'm stuck on this questions thanks
polet [3.4K]
So its asking for basically the percentage of the first number out of the second. 

3. 25/50 = 50%
4. 125/75 = 167%
5. 32/28 = 114%
6. 7/10 = 70%


Hope this helped!  :)
6 0
3 years ago
I just need no. a please help me to prove this. ​
OleMash [197]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    and         cos A = cos B · cos C

scratchwork:

  A + B + C = π

               A = π - (B + C)

         cos A = cos [π - (B + C)]                              Apply cos

                    = - cos (B + C)                                    Simplify

                    = -(cos B · cos C - sin B · sin C)          Sum Identity

                    = sin B · sin C - cos B · cos C               Simplify

cos B · cos C = sin B · sin C - cos B · cos C               Substitution

2cos B · cos C = sin B · sin C                                        Addition

                     2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}                                     Division

                     2 = tan B · tan C

\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}

<u>Proof LHS → RHS</u>

Given:                              A + B + C = π

Subtraction:                     A = π - (B + C)

Apply tan:                  tan A = tan(π - (B + C))

Simplify:                               = - tan (B + C)

\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)

Substitution:                        = -(tan B + tan C)/(1 - 2)

Simplify:                               = -(tan B + tan C)/-1

                                            = tan B + tan C

LHS = RHS:   tan B + tan C = tan B + tan C  \checkmark

5 0
3 years ago
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