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JulijaS [17]
2 years ago
5

If m∠EBF = 6x + 4 and m∠CBF = 7x – 2, find m∠EBF.

Mathematics
2 answers:
olganol [36]2 years ago
6 0

Answer:

78

Step-by-step

I hope it's helped

lukranit [14]2 years ago
5 0

Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?

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each of the 28 students in romi's class raised at least $25 during the jump-a-thon. what is the least amount of money the class
AlladinOne [14]

Answer:

$700

Step-by-step explanation:

25 the least amount of money earned by each student multiplied by 28 the number of students.

4 0
3 years ago
People are surveyed about what sports they play. The results are shown in the frequency table. What graph would best display the
Marrrta [24]

Answer: Bar Graph

Step-by-step explanation:

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3 years ago
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Emily and Miranda are standing outside. Emily is 5 feet tall and casts a shadow of 28 inches. Miranda's shadow is 29.4 inches lo
Andre45 [30]
I think the answer is 5 feet 3 inches
8 0
3 years ago
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What is 2+2
ad-work [718]

Answer:

4

Step-by-step explanation:

2+2 is 4

5 0
3 years ago
If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

6 0
3 years ago
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