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2 years ago

If m∠EBF = 6x + 4 and m∠CBF = 7x – 2, find m∠EBF.

Mathematics

2 answers:

olganol [36]2 years ago

6 0

Answer:

Step-by-step

I hope it's helped

lukranit [14]2 years ago

5 0

Traders have invested $ 100,000 in the Peace Garden Center to boost the capital Mogadishu and make a profit. looga farm income to make people come to the door to take the free tickets for different values $ 0.8 adults and 0.6 children. As many as 150 tickets were sold on Friday for $ 102. produce more child tickets than adult tickets?

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The equation V = 16300 (0.94)^t represents the value (in dollars) of a car t years after its purchase. Use this equation to comp

Dafna1 [17]

Solution:

Given:

$V=16300(0.94)^t$

The value of a car after t - years will depreciate.

Hence, the equation given represents the value after depreciation over t-years.

To get the rate, we compare the equation with the depreciation formula.

$\begin{gathered} A=P(1-r)^t \\ \text{where;} \\ P\text{ is the original value} \\ r\text{ is the rate} \\ t\text{ is the time } \end{gathered}$

Hence,

$\begin{gathered} V=16300(0.94)^t \\ A=P(1-r)^t \\ \\ \text{Comparing both equations,} \\ P=16300 \\ 1-r=0.94 \\ 1-0.94=r \\ r=0.06 \\ To\text{ percentage,} \\ r=0.06\times100=6\text{ \%} \\ \\ \text{Hence, } \\ P\text{ is the purchase price} \\ r\text{ is the rate} \end{gathered}$

Therefore, the value of this car is decreasing at a rate of 6%. The purchase price of the car was $16,300.

5 0

11 months ago

Why do you think you need to add zero pairs to get the -1- tiles to fit in the rectangle?

Olin [163]

You will need. 1- to fit the rectangle tile in

7 0

3 years ago

A tank hold a volume of 32m3 what is the new volume of an enlarged tank of the scale factor is 5 ?

kirill [66]

Answer:

The new volume of an enlarged tank is 4000m³

Step-by-step explanation:

The scale factor has to be multiplied by the width, length and height so we will have to multiply it 3 times

h * w * l = 32 m³

(h*5) * (w*5) * (l*5)

if we rearrange the multiplications

(h * w * l) * 5 *5 * 5 =

v * 5 * 5 * 5 =

32m³ * 5 *5 *5 = 4000m³

4 0

3 years ago

Write a variable expression for each word phrase: the product of c and 3

mash [69]

Variables are symbols that are used to represent a number in an expression or equation.

There's one word phrase here, and it's answer is: c*3

If you need help with another one, just let me know! :)

7 0

3 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago