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spayn [35]
3 years ago
7

Question is in picture

Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0
A^2 + b^2 = c^2
9^2 + 12^2 = 225
square root of 225 is 15
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A positive real number is 6 less than another. If the sum of the square of the two numbers is 38, then finds the numbers.
Serggg [28]

Answer:

There seems to be a typo error but still this has solution.

Let the number be = x

A positive real number is 6 less than another. Means the second will be (x+6)

The sum of the square of the two numbers is 38.

x^{2} +(x+6)^{2} =38  

=> x^{2} +36+12x+x^{2} =38

=> 2x^{2}+12x+36 =38

=> 2x^{2}+12x=2

=> 2x^{2}+12x-2=0

Taking out 2 common;

=> x^{2}+6x-1=0

Solving this quadratic equation, we get;

x=-3+\sqrt{10} and x=-3-\sqrt{10}

As positive number is needed, we have -3+\sqrt{10}

or x = \sqrt{10}-3

x = 0.162277

And other number is 6.162277.

6 0
3 years ago
Read 2 more answers
$270.20 divided by 28
NISA [10]
9.65 hope I helped you
6 0
3 years ago
Read 2 more answers
Help ppppppppppppllllllllllllllllsssssssss
nlexa [21]

Answer:

The answer is tan²Ф + 1 = sec²Ф

Step-by-step explanation:

∵ sin²Ф + cos²Ф = 1 ⇒ ÷ cos²Ф both sides

∴ sin²Ф/cos²Ф + cos²Ф/cos²Ф = 1/cos²Ф

∵ sin²Ф/cos²Ф = tan²Ф

∵ 1/cos²Ф = sec²Ф

∴ tan²Ф + 1 = sec²Ф

3 0
3 years ago
I need help really badly please
Stolb23 [73]

Answer:

  y = 26

Step-by-step explanation:

The angles of a linear pair total 180°.

__

  (2y +1)° +(5y -3)° = 180° . . . . the sum of the angles is 180°

  7y -2 = 180 . . . . . . divide by °, collect terms

  7y = 182 . . . . . . . . add 2

  y = 26 . . . . . . . . . divide by 7

_____

<em>Additional comment</em>

The angle measures are (2(26) +1)° = 53°, and (5(26) -3)° = 127°. These total 180°, as they should.

6 0
2 years ago
Algebraically find the point where the cable and the strut intersect. Interpret your answer. (10 points)
sweet-ann [11.9K]

Answer:

√2x+8=x-8

2x+8=x^2-16x+64

-x^2+18x-56=0

x^2-18x+56=0

x(x-4)-14(x-4)=0

(X-4)(x-14)=0

x=4(extraneous) ,x=14

—> x=14

Step-by-step explanation:

8 0
3 years ago
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