Question

Urgent:

Answer 1

Step-by-step explanation:

Given:

• CM ⊥ AB
• ∠3 = ∠4

To prove:

• △AMC ≅ △BMC

Solution:

• ∠ACM≅∠BCM - given

CM⊥AB - given, therefore

• ∠AMC = 90° and ∠BMC = 90°

Then

• ∠AMC ≅ ∠BMC

• Side CM is common, therefore is congruent to itself

So we have congruent two angles and a side between them on triangles AMC and BMC:

• △AMC ≅ △BMC as per ASA congruency theorem