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grigory [225]
3 years ago
15

In which number does the digit 777 have a value that is 101010 times as great as the digit 777 in the number 0.9750.9750, point,

975?
Mathematics
1 answer:
masya89 [10]3 years ago
4 0

Answer:

0.73

Step-by-step explanation:I use khan too 0.7 is 10 times as great as 0.07

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2/3÷2 1/3= dividing fractions
wolverine [178]

Answer:

3/3

Step-by-step explanation:

3/3

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20 POINT QUESTION!!!
Mazyrski [523]

Answer:

Graph A

Step-by-step explanation:

For each piece of the function the first number is included (0, 4, 8) and second number excluded (4, 8, 12). Included points are solid and excluded are open dots.

It's correctly reflected in A graph only.

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suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1). Write the eq
lesya [120]

Answer:

<h3>            f(x) = - 3(x + 8)² + 2</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k   - the vertex form of the quadratic function with vertex    (h, k)

the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8

the <u>maximum height of 2</u> means  k = 2

So:

f(x) = a(x - (-8))² + 2

f(x) = a(x + 8)² + 2   - the vertex form of the quadratic function with vertex   (-8, 2)

The parabola passing through the point (-7, -1) means that if x = -7 then        f(x) = -1

so:

    -1 = a(-7 + 8)² + 2

 -1 -2 = a(1)² + 2 -2

      -3 = a

Threfore:

The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:

                                 <u>f(x) = -3(x + 8)² + 2</u>

8 0
3 years ago
Write an equation for the sentence below. Then solve the equation.
Romashka-Z-Leto [24]
The answer is D thirteen multiplied by h is 13h. The word "is" typically means = so 13h=104. to solve for this you want to isolate the h on one side of the equation. to do this we need to get rid of the 13 and move it on the other side of the equation. the new equation is h=104÷13. So, h=8. Hope this helps! 
6 0
3 years ago
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A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
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