What is the least common denominator for fractions that have denominators of 5x+10 and 25x^2-100
Answer:
1:4
Step-by-step explanation:
A ratio can be written like this: 15:60, but it can also be written as the fraction 15/60, which can be simplified to 1/4, or 1:4.
Answer:
80
Step-by-step explanation:
First recall that:
1 inch=12 feet
The volume of cube-shaped boxes with 12-inch edges is 1 cm³
The volume of a box that is 4
feet tall, 4 feet long, and 5 feet wide is
given by:
We substitute l=4ft, w=5ft and h=4ft
To obtain:
Therefore 80 cube-shaped boxes with 12-inch edges can fit into a box that is 4
feet tall, 4 feet long, and 5 feet wide.
The scale factor that Thea uses to go from Rectangle Q to Rectangle R is equal to 6.
<h3>What is the scale factor from rectangle Q to rectangle R?</h3>
In geometry, the scale factor is a ratio of the resulting length to the initial length. Since the area of the square is equal to the square of its side length, then the scale factor is equal to:
k² = A' / A
k = √(A' / A)
Where:
- k - Scale factor
- A' - Area of the rectangle R.
- A - Area of the rectangle Q.
If we know that A = 2 and A' = 72, then the scale factor is:
k = √(72 / 2)
k = √36
k = 6
Then, the scale factor that Thea uses to go from Rectangle Q to Rectangle R is equal to 6.
To learn more on scale factors: brainly.com/question/22312172
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So we first minus 6 both sides
7x^2-14x=-6
then we have
A(x^2-2x)=-6
what is A?
hmm (this should be painfully obvous, but if not, here are steps)
7x^2-14x=-6
A(x^2-2x)=-6
7x^2-14x=-6=A(x^2-2x)
7x^2-14x=A(x^2-2x)
undistribute 7
7(x^2-2x)=A(x^2-2x)
divide both sides by (x^2-2x)
7=A
A=7
