A right triangle can only be formed when you use the 3/4/5 rule.
The 3/4/5 rule is a^2 + b^2 = c^2.
We will use 10 for a, 15 for b, and 20 for c.
a^2 + b^2 = c^2
Plug in 10 for a, 15 for b, and 20 for c.
10^2 + 15^2 = 20^2
10^2 = 100
15^2 = 225
20^2 = 400
100 + 225 = 400
This is not applicable, as 100 + 225 = 325.
Your answer is:
No, 10,15,20 does not form a right triangle.
I hope this helps!
Answer:
C
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Given
y = 2x² + 12x + 1
To express in vertex form use the method of completing the square.
The coefficient of the x² term must be 1 , thus factor out 2 from 2x² + 12x
y = 2(x² + 6x) + 1
add/ subtract ( half the coefficient of the x- term)² to x² + 6x
y = 2(x² + 2(3)x + 9 - 9) + 1
= 2(x + 3)² - 18 + 1
= 2(x + 3)² - 17 → C
The answer will be C. I hope this helped you! ^^
Answer:
x
=9
y
=2
Step-by-step explanation:
2ty'=4y
Replacing y'=dy/dt in the equation:
2t(dy/dt)=4y
Grouping terms:
dy/y=4dt/(2t)
dy/y=2dt/t
Integrating both sides:
ln(y)=2ln(t)+ln(c), where c is a constant
Using property logarithm: b ln(a) = ln(a^b), with b=2 and a=t
ln(y)=ln(t^2)+ln(c)
Using property of logarithm: ln(a)+ln(b) = ln(ab), with a=t^2 and b=c
ln(y)=ln(ct^2)
Then:
y=ct^2
Using the initial condition: y(2)=-8
t=2→y=-8→c(2)^2=-8→c(4)=-8
Solving for c:
c=-8/4
c=-2
Then the solution is y=-2t^2
Comparing with the solution: y=ct^r
c=-2, r=2
Answer: T<span>he value of the constant c is -2 (c=-2) and the exponent r is 2 (r=2)</span>
