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jeyben [28]
3 years ago
10

Please solve quickly, will give brainliest

Mathematics
2 answers:
nalin [4]3 years ago
8 0

Answer:

Step-by-step explanation:

for 1 cube of 6 sides, it takes 5 grams

so 1 side is 5/6th grams

now how many sides of small cubes are shown is 42

42*5/6=35 grams

fenix001 [56]3 years ago
8 0

Answer:

180 grams

Step-by-step explanation:

5gramsx number of squares

5gramsx 36=180grams

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U Make It is having a 20% off your entire purchase sale. Rebecca is buying 6 skeins of yarn. Each skein costs $3.95. The tax on
maxonik [38]

Answer:

The correct answer is option D

Step-by-step explanation:

Number of yarns purchased by Rebecca = 6\\

Cost of one yarn = 3.95\\

Cost of 6 yarn = 6 * 3.95\\

Cost of 6 yarn after discount of 20\\ %

= 6 * 3.95 * 0.8\\

Cost after tax of 8%

(6 * 3.95 * 0.8) + 0.08 (6 * 3.95 * 0.8)\\= 1.08 (6 * 3.95 * 0.8)\\

8 0
4 years ago
Read 2 more answers
Please help me with this it’s due soon
KonstantinChe [14]

Answer:

39.5 degrees

Step-by-step explanation:

180-101=79

79/2=39.5

3 0
3 years ago
Read 2 more answers
Which ordered pair is not a solution of y = -3x + 4
lakkis [162]
Test
remember, (x,y)

A.
10=-3(-2)+4
10=6+4
10=10
yep, this is a soltuion

B.
5=-3(3)+4
5=-9+4
5=-5
false, not a solution

C.
4=-3(-2)+4
4=6+4
4=10
nope, not a solution

D.
1=-3(1)+4
1=-3+4
1=1
true

hmm, I think if B was (3,-5) then C is the only one


C is the answer
3 0
3 years ago
Entomologists have discovered that a linear relationship exists between the rate of chirping of crickets of a certain species an
vekshin1

Answer:

a) y=4x-160

b) y=4(102)-160=248\frac{chirps}{min}

Step-by-step explanation:

We know that theres a <u><em>linear relationship</em></u> between the rate of the chirping of crickets and the air temperature.

<u><em>The equation of a line is</em></u>:

y=mx+b

So, let's name our variables

x= Temperature

y=Rate of the chirping

First of all, we need to find the <u><em>slope</em></u> with the two given points

x_{1}=60ºF , y_{1} =80\frac{chirps}{min}

x_{2} =80ºF, y_{2} =160\frac{chirps}{min}

By,

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  } =\frac{160-80}{80-60}

m=4

<u>Now, the </u><em><u>equation</u></em><u> between the air temperature and the number of chirps is:</u>

y-y_{1} =m(x-x_{1} )

y-80=4(x-60)

Solving for y,

a) y=4x-160

b) <u>To calculate the </u><u>rate</u><u> at which the crickets chirp when the </u><u>temperature is 102 ºF</u><u> we need to evaluate y(102)</u>

y=4(102)-160=248\frac{chirps}{min}

5 0
3 years ago
3 5<br> What is of = ? Simplify.<br> 8 6<br> -
Verizon [17]
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7 0
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