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IrinaK [193]
2 years ago
8

Solve: (a+b+c) (a+b-c)

Mathematics
2 answers:
Katen [24]2 years ago
7 0

Answer:

<h2><u><em>a²+2ab+b²-c²</em></u></h2>

Step-by-step explanation:

Solve:

(a+b+c) (a+b-c)=

(a²+ab-ac+ab+b²-bc+ac+bc-c²)=

a²+ab-ac+ab+b²-bc+ac+bc-c²=

a²+2ab+0ac+b²+0bc-c²=

a²+2ab+b²-c²

zvonat [6]2 years ago
4 0

Answer:

The answer is a² + 2ab + b² - c²

Step-by-step explanation:

(a + b + c) × (a + b - c)

a² + ab - ac + ba + b² - bc + ca + cb - c²

a² + ab + ba - ac + ca + b² - bc + cb - c²

a² + 2ab + b² - c²

Thus, The answer is a² + 2ab + b² - c²

<u>-TheUnknownScientist</u><u> 72</u>

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Gre4nikov [31]

In this picture dots are clearly shown the frequency of the concert.

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Here, in given data about the six concerts

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