Answer: Hypoxia
Explanation: hypoxia induces the production of erythropoietin, which is a hormome produced by the kidneys to help increase the productiom of red blood cells in the body. In Jessica's case, she might be experiencing this due to a change in ultitide whereby her body needs more oxygen than it originally gets (crllular hypoxis), therefore, her body signals for more red blood cell production. The erythropoietin will then be secreted and more red blood cells will be formed by the bone marrow through the hormonal action.
Air would go through the trachea, then the bronchi, the bronchioles, and then the alveoli.
mRNA plays a crucial role in protein synthesis. It carries the information for synthesis of a particular protein from the DNA to the ribosomes.
In the cell nucleus, this information is copied (transcribed ) from DNA and onto mRNA. mRNA then leaves the nucleus and enters the cytoplasm where it attaches to a ribosome.
Transfer RNA or tRNA begins to read (translate) the information on the attached mRNA and from the pool of free amino acids in the cytoplasm, fetches the amino acids that corresponds to the information, and brings them to the ribosome where they are linked together into a chain, forming the primary structure of protein.
I will say that the answer to your his question is letter A
Answer:
FfPp
Explanation:
If we take the two traits to be separate alleles, we can make flowers F (F is dominant; f is recessive) and pollen as P (P is dominant; p is recessive). So a pea plant with white flowers (recessive) and long pollen (dominant) will have the genotype ffPp or ffPP (because one dominant allele will express a dominant phenotype).
For this question, we will assume that the wild type (red flowers and long pollen) is homozygous, meaning it contains two dominant alleles.
If the wild type (FFPP) is crossed with the plant with white flowers and short pollen (ffpp), we can make a table illustrating the crosses. However, because there is only one possible gamete that each parent can form (FP and fp), we can assume that the F1 progeny will have identical genotypes, which can be expressed as FfPp (because combining the gamete from the wild type and the other parent can only give one phenotype).