Given that Erica and AAron,are using lottery system to decide who will wash dishes every night.
They put some red and blue power chips and draw each one. If same colour, Aaron will wash and if not same colours Erica will wash
If the game is to be fair, then both should have equal chances of opportunity for washing.
i.e. Probability for Erica washing = Prob of Aaron washing
i.e. P(different chips) = P(same colour chips)
Say there are m red colours and n blue colours.
Both are drawing at the same time.
Hence Prob (getting same colour) = (mC2+nC2)/(m+n)C2
Probfor different colour = mC1+nC1/(m+n)C2
The two would be equal is mC2 +nC2 = m+n
This is possible if mC2 =m and nC2 = n.
Or m = 2+1 =3 and n =3
That for a fair game we must have both colours to be 3.
The tax bracket and tax-free yield will be (18%, 3%) < (32%, 3%) < (32% , 4%) < (22% , 5%) < (24% , 6%) .
<h3>
Taxable equivalent yield based problem:</h3>
The taxable equivalent yield will be:
= Tax-free yield / (100 - Tax bracket)
Taxable equivalent yield = 3 / (100 - 18) = 0.03659
Taxable equivalent yield = 6 / (100 - 24) = 0.07895
Taxable equivalent yield = 3 / (100 - 32) = 0.04412
Taxable equivalent yield = 5 / (100 - 22) = 0.06410
Taxable equivalent yield = 4 / (100 - 32) = 0.05882
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Answer:
27
Step-by-step explanation:
Okay you have 2 sum unknow lets call them X+Y
so X+Y=33, 4X=108
Get X by it self then plug it in 4X=108
X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out
-2x^2 + 3x - 9 = 0
The quadratic is not factorable so quadratic formula must be used.
x = (-b + - √(b^2 - 4ac))/2a
a = -2, b = 3, c = -9
x = (-3 + - √(9 - 4*-2*-9))/-4
x = (-3 + - √(-63))/-4
x = -3 + - 3i√7
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-4
x = 3 + 3i√7 x = 3 - 3i√7
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4 4