Answer:
Step-by-step explanation to be honest probably 12 if not i’m so sorry
Answer:
The length of the field on the drawing is 55 cm.
Step-by-step explanation:
Given:
Mark made a scale drawing of a soccer field.
Using a scale of .5 cm=1 m.
The actual length of the field is 110 m.
Now, to find the length of the field on drawing.
Let the length of the field on drawing be 
As given 0.5 cm is equivalent to 1 m.
Thus, 
is equivalent to 110 m.
Now, to get the length of the field on drawing by using cross multiplication method:
<em>By cross multiplying we get:</em>
⇒ 
⇒ 
Therefore, the length of the field on the drawing is 55 cm.
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Root: A/2 is the equation
your answer is 1.38
