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2 years ago

Can someone help me with this problem please??

Mathematics

1 answer:

kifflom [539]2 years ago

3 0

Answer:

Hi mate

I would advise you to make an account with the location given as india

They are helpful as hell with such questions

Hope helps mate ❤️

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Need help with math pls help me will mark brainiest.

saw5 [17]

Answer:

The slope is $\frac{-1}{3}$ .

Step-by-step explanation:

Math Vocabulary Values

Vertical Change -1

Horizontal Change 3

Slope $\frac{-1}{3}$

8 0

2 years ago

Find the distance between the following pairs of points: C (1,6) .D (13.41).

worty [1.4K]

The person above is correct

8 0

2 years ago

The sum of two numbers is 33.the larger number is 3 more than two times the smaller number.what are the numbers?

e-lub [12.9K]

Answer: The numbers are 10 and 23

Step-by-step explanation:

Let the smaller number be x

And the larger number be y

Ist sentence;

1. The sum of two numbers is 33.

X + y= 33 .........eqn 1

2. second sentence

the larger number is 3 more than two times the smaller number.

Y = 3 +2x

Put y into eqn 1

X+ 3 +2x = 33

3x= 33- 3

3x= 30

X = 30/3

X= 10 and y= 3+ 2x

Y= 3+ 2(10)

Y = 3+ 20

Y= 23

Therefore the two numbers are 10 and 23

8 0

3 years ago

What is the diameter of a circle if the circumference is 11?

Gennadij [26K]

Answer:

d≈3.5

Step-by-step explanation:

d= C/π =11/π≈3.50141

Brainliest plz

7 0

3 years ago

In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the

emmasim [6.3K]

Answer:

$a=\frac{2S -2v_ot-2s_o}{t^2}$

Step-by-step explanation:

We have the equation of the position of the object

$S = \frac{1}{2}at ^2 + v_ot+s_o$

We need to solve the equation for the variable a

$S = \frac{1}{2}at ^2 + v_ot+s_o$

Subtract $s_0$ and $v_0t$ on both sides of the equality

$S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o$

$S -v_ot-s_o = \frac{1}{2}at ^2$

multiply by 2 on both sides of equality

$2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2$

$2S -2v_ot-2s_o =at ^2$

Divide between $t ^ 2$ on both sides of the equation

$\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}$

Finally

$a=\frac{2S -2v_ot-2s_o}{t^2}$

5 0

2 years ago