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son4ous [18]
3 years ago
14

Evaluate (x2 + y2) dv e , where e lies between the spheres x2 + y2 + z2 = 9 and x2 + y2 + z2 = 16.

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0
Convert to spherical coordinates, using

x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi
y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi
z(\rho,\theta,\varphi)=\rho\cos\varphi

The volume element is

\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

In spherical coordinates, the two given spheres are obtained by setting \rho=3 and \rho=4. So the integral evaluates to

\displaystyle\iiint_{\mathcal E}(x^2+y^2)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=3}^{\rho=4}\rho^2\sin^2\varphi(\rho^2\sin\varphi)\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi
=\dfrac{6248\pi}{15}
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Simplify (5+11i) - (16-4i) +9i.
lisabon 2012 [21]

Answer:

5+11i-16-4i+9i

5-16+11i-4i+9i

-11+7i+9i

-11+16i

Step-by-step explanation:

First, get the like terms together. Then add or subtract until its simplified. Simplified is -11+16i.

6 0
2 years ago
Read 2 more answers
What is the value of q?
andre [41]

Answer: here

Step-by-step explanation:riangles QST and RST are similar.  Therefore, the following is true:

q       s

--- = ----   This results in 10q=rs.

r      10

Also, since RST is a right triangle, 4^2 + s^2 = q^2.

Since QST is also a right triangle, s^2 + 10^2 = r^2.  

           4      s

Also:  ---- = -----    which leads to s^2 = 40

           s      10

Because of this, 4^2 + s^2 = q^2 becomes 16 + 40 = 56 = q^2

Then q = sqrt(56) = sqrt(4)*sqrt(14) = 2*sqrt(14) (answer)

hope it helps

6 0
2 years ago
At a bake sale, as student spent $11.00 buying 3 brownies and 5 cookies. His friend spent $3.95 buying 1 brownie and 2 cookies.
dybincka [34]

Answer:

$2.25

Step-by-step explanation:

Let "b" be the price of 1 brownie and "c" the price of 1 cookie.

At a bake sale, a student spent $11.00 buying 3 brownies and 5 cookies. Symbolicaly,

3 b + 5 c = 11.00   [1]

His friend spent $3.95 buying 1 brownie and 2 cookies. Symbolicaly,

1 b + 2 c = 3.95

b = 3.95 - 2c   [2]

If we replace [2] in [1], we get

3 (3.95 - 2c) + 5 c = 11.00

11.85 - 6c + 5c = 11.00

c = 0.85

If we replace c = 0.85 in [2], we get

b = 3.95 - 2 (0.85) = 2.25

8 0
3 years ago
While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

While solving an equation, if we obtain an equation which is mathematically correct such as 0=0, 7=7 etc., then the equation will have infinietly many solutions. So, infinitely many solutions is chosen when no value is obtained for n and the final equation is mathematically correct.

8 0
10 months ago
Question 16 (Essay Worth 7 points)<br><br> Verify the identity.<br><br> tan (x + π/2) = -cot x
Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

\frac{sin(x+pi/2)}{cos(x+pi/2)}

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)}  = \frac{cos(x)}{cos(x+\pi/2) }

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)

6 0
2 years ago
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