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lys-0071 [83]
3 years ago
13

Rob had twice as much money as Sam. Then Sam gave Rob 1 quarter, 2 nickels, and 3 pennies. Rob then gave Sam 8 dimes. If they no

w have the same amount of money, how much money did Rob originally have? (Steps please!)
Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

Let the initial amount that Sam had be x.

Then, since Rob had twice as much as Sam, Rob's money would be 2x.

Now, Sam gave 1 quarter, 2 nickels and 3 pennies to Rob.

Let's convert all of them into pennies.

1 quarter + 2 nickels + 3 pennies = 25 + (2 x 5) + 3

                                                      = 38 pennies

So, Sam's amount is x - 38 and Rob's amount is 2x + 38.

Now, Rob gives 8 dimes to Sam.

8 dimes = 80 pennies.

So, Sam's amount now is x - 38 + 80 = x + 42 and

Rob's amount is 2x + 38 - 80 = 2x - 42

Its given that these two amounts are same.

So,  2x - 42 = x + 42

2x - x = 42 + 42

x = 84

Rob's original amount = 2x = 2(84) = 168 pennies.

                                                         = $1 + 6 dimes + 1 nickel + 3 pennies

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<h2>1. The "required option c) 45" is correct.</h2><h2>2. The value of 8 − 2⋅3 + 7 = 9</h2><h2>3. The required "option c) 45" is correct.</h2><h2>4. The required "option a) 40" is correct.</h2><h2>5. The value of 3^2-2.3+5 = 8</h2>

Step-by-step explanation:

1. We have,

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To find, the value of 5^2 + 20 = ?

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2. We have,

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4. We have,

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To find, the value of 2^{3} +4.8 = ?

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Thus, the value of 2^{3} +4.8 = 40

Thus, the required "option a) 40" is correct.

5 . We have,

3^2-2.3+5

To find, the value of 3^2-2.3+5 = ?

∴ 3^2-2.3+5

= 3 × 3 - 2 × 3 + 5

= 9 - 6 + 5

= 14 - 6

= 8

Thus, the value of 3^2-2.3+5 = 8

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