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4 years ago

given the equation -4 square root of x-3=12, solve for x and identify if it is an extraneous solution

Mathematics

1 answer:

pogonyaev4 years ago

3 0

I don't remember what is a extraneous solution, but i hope it helps

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3 years ago

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What is the product of 6(x^2-1) * 6x-1/6(x+1)

umka2103 [35]

(6(x^2-1))*((6x-1)/(6(x+1))
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3 years ago

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kicyunya [14]

Answer:

Option c) y= $3\frac{17}{25}$ is correct

The value of y is 3 $\frac{17}{25}$

Step-by-step explanation:

Given equation is

$y-\frac{12}{25}=3\frac{1}{5}$

To solve the given equation for y

$y-\frac{12}{25}=3\frac{1}{5}$

$y-\frac{12}{25}=\frac{16}{5}$ (converting mixed fraction to normal fraction )

$y-\frac{16}{5}=\frac{12}{25}$

$y-\frac{(16\times 5)+12}{25}$ (taking LCM 25 )

$=\frac{80+12}{25}$ (adding the terms )

$y=\frac{92}{25}$ (now convert fraction into mixed fraction )

Therefore y= $3\frac{17}{25}$

Option c) y= $3\frac{17}{25}$ is correct

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3 years ago

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3 years ago

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nydimaria [60]

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