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bija089 [108]
3 years ago
12

Find the greatest common factor of 24, 64, 108.

Mathematics
1 answer:
Ainat [17]3 years ago
6 0

Answer:

The answer is 4.

Step-by-step explanation:

To find the greatest common factor (GCF), start by listing the factors of each number.

For 24: 1, 2, 3, 4, 6, 8, 12, 24

For 64: 1, 2, 4, 8, 16, 32, 64

For 108: 1, 2, 3, 4, 6, 9, 12, 18

Since all the factors are now written out, we can find the greatest common factor between 24, 64, and 108, and the GCF is 4.

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Step-by-step explanation:

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Travis needs to slow down

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3 years ago
Omar scored and 82% on his first test of the quarter.will score of 38 out of 50 on the second test help or hurt his grade?
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3 years ago
How many integers between 10 and 60, inclusive, can be evenly divided by neither 2 nor 3?
erastovalidia [21]
Find total number of integers.

a_1=10,a_n=60,d=1 \\a_n=a_1+(n-1)d \\60=10+(n-1)1 \\n-1=50 \\n=51

Find how many integers is divisible by 2.

a_1=10,a_n=60,d=2&#10;\\a_n=a_1+(n-1)d&#10;\\60=10+(n-1)2&#10;\\2(n-1)=50&#10;\\n-1=25&#10;\\n=26

Eliminate even numbers.

11, 13, 15,..., 57, 59

This array contains 51 - 26 = 25 numbers.

Eliminate numbers before the first number divisible by 3 and after the last number divisible by 3.

15, 17, 19,..., 55, 57

This array contains 25 - 3 = 22 numbers.

Now we should eliminate numbers divisible by 3: 15, 21, 27...

a_1=15,a_n=57,d=6,n=?&#10;\\a_n=a_1+(n-1)d&#10;\\57=15+(n-1)6&#10;\\6(n-1)=42&#10;\\n-1=7&#10;\\n=8

There are 8 such numbers.

Therefore, there are 25 - 8 = 17 numbers that <span>can be evenly divided by neither 2 nor 3</span>

6 0
3 years ago
Hi pls help me!!! thank you
elena-s [515]

Step-by-step explanation:

Circumference (C):

C = 2\pi r = 2\pi(5\:\text{ft}) = 31.4\:\text{ft}

Area (A):

A = \pi r^2 = \pi(5\:\text{ft})^2 = 78.5\:\text{ft}^2

6 0
2 years ago
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