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3 years ago

A fish dives 3 ft per minute estimate how far the fish will be in 15 minutes

Mathematics

1 answer:

Anarel [89]3 years ago

4 0

Answer: 45 ft

Step-by-step explanation: 3 times 15 equals 45

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8x + y = 9 Convert the following equations to standard form

Citrus2011 [14]

Answer:

x=1/8y+9/8

y=y=−8x+9

Step-by-step explanation:

Let's solve for y.

8x+y=9

Step 1: Add -8x to both sides.

8x+y+−8x=9+−8x

y=−8x+9

Let's solve for x.

8x+y=9

Step 1: Add -y to both sides.

8x+y+−y=9+−y

8x=−y+9

Step 2: Divide both sides by 8.

8x/8=−y+9/8

x=−1/8y+9/8

5 0

3 years ago

More than half of 2000.00 equals how much

lina2011 [118]

1000 IS THE ANSWER EJN3;RVLGBPOIJGNTIOG;K

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3 years ago

What are the value(s) for K? 7K^3=56 Please show your work

Phoenix [80]

I hope this helps you

6 0

3 years ago

What is 273 ft equal to in yd? And why?

Ivenika [448]

That would be 91 yrd, just divide 273 by 3 because there is 3 ft in a yard

Hope this helps!

3 0

3 years ago

Read 2 more answers

An open box with a square base is constructed so that it has a volume of 64in^3. The base needs to be made out of a material tha

Ivahew [28]

The volume of a box is the amount of space in the box

The dimensions that minimize the cost of the box is 4 in by 4 in by 4 in

<h3>How to determine the dimensions that minimize the cost</h3>

The dimensions of the box are:

Width = x

Depth = y

So, the volume (V) is:

$V = x^2y$

The volume is given as 64 cubic inches.

So, we have:

$x^2y = 64$

Make y the subject

$y = \frac{64}{x^2}$

The surface area of the box is calculated as:

$A =x^2 + 4xy$

The cost is:

$C = 2x^2 + 4xy$ --- the base is twice as expensive as the sides

Substitute $y = \frac{64}{x^2}$

$C = 2x^2 + 4x * \frac{64}{x^2}$

$C =2x^2 + \frac{256}{x}$

Differentiate

$C' =4x - \frac{256}{x^2}$

Set to 0

$4x - \frac{256}{x^2} = 0$

Multiply through by x^2

$4x^3 - 256= 0$

Divide through by 4

$x^3 - 64= 0$

Add 64 to both sides

$x^3 = 64$

Take the cube roots of both sides

$x = 4$

Recall that:

$y = \frac{64}{x^2}$

So, we have:

$y = \frac{64}{4^2}$

$y = 4$

Hence, the dimensions that minimize the cost of the box is 4 in by 4 in by 4 in