The answers are x=0 and y=1
Answer:
B. lines BE and CG have to be parallel.
Step-by-step explanation:
Answer:
The number of games must a store sell in order to be eligible for a reward is 135.
Step-by-step explanation:
Let the random variable <em>X</em> represent the number of video games sold in a month by the sores.
The random variable <em>X</em> has a mean of, <em>μ</em> = 132 and a standard deviation of, <em>σ</em> = 9.
It is provided that the company is looking to reward stores that are selling in the top 7%.
That is,
.
The <em>z</em>-score related to this probability is, <em>z</em> = 1.48.
Compute the number of games must a store sell in order to be eligible for a reward as follows:
![z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B%5Cbar%20x-%5Cmu%7D%7B%5Csigma%2F%5Csqrt%7Bn%7D%7D)
![\bar x=\mu+z\cdot \sigma/\sqrt{n}](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cmu%2Bz%5Ccdot%20%5Csigma%2F%5Csqrt%7Bn%7D)
![=132+1.48\times (9/\sqrt{36})\\\\=132+2.22\\\\=134.22\\\\\approx 135](https://tex.z-dn.net/?f=%3D132%2B1.48%5Ctimes%20%289%2F%5Csqrt%7B36%7D%29%5C%5C%5C%5C%3D132%2B2.22%5C%5C%5C%5C%3D134.22%5C%5C%5C%5C%5Capprox%20135)
Thus, the number of games must a store sell in order to be eligible for a reward is 135.
Answer:
Area of triangle is 25.
Step-by-step explanation:
We have been given an isosceles right triangle
Isosceles triangle is the triangle having two sides equal.
Figure is shown in attachment
By Pythagoras theorem
![BC^2=AC^2+AB^2](https://tex.z-dn.net/?f=BC%5E2%3DAC%5E2%2BAB%5E2)
AD is altitude which divides the triangle into two parts
DC=5 implies BC =10 since D equally divides BC
Let AC=a implies AB=a being Isosceles
On substituting the values in the Pythagoras theorem:
![10^2=a^2+a^2](https://tex.z-dn.net/?f=10%5E2%3Da%5E2%2Ba%5E2)
![100=2a^2](https://tex.z-dn.net/?f=100%3D2a%5E2)
![\Rightarrow a^2=50](https://tex.z-dn.net/?f=%5CRightarrow%20a%5E2%3D50)
![\Rightarrow a=\pm5\sqrt{2}](https://tex.z-dn.net/?f=%5CRightarrow%20a%3D%5Cpm5%5Csqrt%7B2%7D)
WE can find area of right triangle by considering height AB and AD
Area of triangle ABC is:
(1)
![\Rightarrow \frac{1}{2}\cdot 10\cdot AD](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%2010%5Ccdot%20AD)
And other method of area of triangle is:
(2)
Equating (1) and (2) we get:
![\frac{1}{2}\cdot 10\cdot AD=\frac{1}{2}\cdot a\cdot a](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%2010%5Ccdot%20AD%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20a%5Ccdot%20a)
![\Rightarrow AD=\frac{a^2}{10}](https://tex.z-dn.net/?f=%5CRightarrow%20AD%3D%5Cfrac%7Ba%5E2%7D%7B10%7D)
![\Rightarrow AD=\frac{50}{10}=5](https://tex.z-dn.net/?f=%5CRightarrow%20AD%3D%5Cfrac%7B50%7D%7B10%7D%3D5)
Using area of triangle is: ![\frac{1}{2}\cdot BC\cdot AD](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20BC%5Ccdot%20AD)
Now, the area of triangle ABC=![\frac{1}{2}\cdot 5\cdot 10](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ccdot%205%5Ccdot%2010)
![\Rightarrow 25](https://tex.z-dn.net/?f=%5CRightarrow%2025)
It is the 4th one since all of the coefficients and variables can be 3rd rooted without getting an irrational number